按R中的因子过滤数据帧

时间:2012-06-19 10:34:28

标签: r

我有以下数据框:

sp <- combn(c("sp1","sp2","sp3","sp4"),2)
d <- data.frame(t(sp),"freq"=sample(0:100,6))

和两个因素

x1 <- as.factor(c("sp1","sp2"))
x2 <- as.factor(c("sp3","sp4"))

我需要返回一个数据框,其中包含x1x2的所有可能组合以及与此组合相关联的数据框freq中的d

返回的数据框如下所示:

data.frame("X1" = c("sp1","sp1","sp2","sp2"),
           "X2" = c("sp3","sp4","sp3","sp4"),
           "freq" = c(4,94,46,74))

我试过了:

sub <- d[d$X1 == x1 & d$X2 == x2,]

但得到错误

Error in Ops.factor(d$X1, x1) : level sets of factors are different

关于如何解决这个问题的任何想法?

2 个答案:

答案 0 :(得分:5)

你快到了:

d[d$X1 %in% x1 & d$X2 %in% x2,]

答案 1 :(得分:3)

不要提出x1x2因素。只需使用矢量。使用%in%进行逻辑测试。

sp <- combn(c("sp1","sp2","sp3","sp4"),2)
d <- data.frame(t(sp),"freq"=sample(0:100,6))
x1 <- c("sp1","sp2")
x2 <- c("sp3","sp4")
sub <- d[d$X1 %in% x1 & d$X2 %in% x2,]