以下代码可在android设备上运行,但在iOS设备上会引发异常
dynamic _sendEmail() async {
String url = 'mailto:support@test.com?subject=请写以上这个线';
if (await canLaunch(url)) {
await launch(url);
} else {
throw 'Could not launch $url';
}
}
Could not launch mailto:support@k8sllc.com?subject=请写以上这个线
答案 0 :(得分:0)
您应该对网址进行编码:
String url = Uri.encodeComponent('mailto:support@test.com?subject=请写以上这个线');
所以看起来像这样:
mailto%3Asupport%40test.com%3Fsubject%3D%E8%AF%B7%E5%86%99%E4%BB%A5%E4%B8%8A%E8%BF%99%E4%B8%AA%E7%BA%BF