Question

我正在尝试在节点中存储一组int。我没有按照我应该的方式获得节点。任何人都可以提供任何帮助都会很棒。

  public void readIn()
  {
  int counter = 1;
     try {
        Scanner inFile = new Scanner(new FileReader("WordProblemData.txt"));
        int times = Integer.parseInt(inFile.next());
        for (int a = 1;a <= times; a++)
        {
           for (int i = 1; i <= 8; i++)
           {
              num[i-1] = Integer.parseInt(inFile.next());
              System.out.println(num[i-1]);

           }
           data = (String)(inFile.next()); 
           System.out.println(data);



           head = new DateStampNode(data,num,head);
        }
        inFile.close();

Answer 1

除非你有一个预先分配的大型数组，否则我认为你需要在填充之前分配一个新的数组。

您可能还想记住增加num。

Answer 2

我不确定你的问题究竟是什么（你认为应该？），但可能是这样：

int[] num = new int[8]; //you should allocate a new array, otherwise you'd overwrite the values in the next iteration of the outer loop
for (int i = 1; i <= 8; i++)
{
    num[i-1] = Integer.parseInt(inFile.next());
    System.out.println(num[i-1]);
}
data = (String)(inFile.next()); 
System.out.println(data);

//you're storing num here, so you'd need a new num array for the next iteration, see above
head = new DateStampNode(data,num,head);

在节点中存储完整的Array

2 个答案: