输入数据框
data = {
'org_id' :[79,80,21,36,40,7,10,9,12,24],
'r_id' : [79,80,20,20,20,7,7,9,12,12],
'Type_id' : ['P','P','C','C','C','P','C','P','P','C'],
'grp_id': ['g54','g55','g13','g13','g13','g6','g6','g7','g8','g8']
}
df2 = pd.DataFrame.from_dict(data)
df2
Out[271]:
org_id r_id Type_id grp_id
0 79 79 P g54
1 80 80 P g55
2 21 20 C g13
3 36 20 C g13
4 40 20 C g13
5 7 7 P g6
6 10 7 C g6
7 9 9 P g7
8 12 12 P g8
9 24 12 C g8
输出数据框
数据= {
'org_id' :[79,80,21,36,40,7,10,9,12,24],
'r_id' : [79,80,20,20,20,7,7,9,12,12],
'Type_id' : ['C','C','C','C','C','P','C','C','P','C'],
'grp_id': ['g54','g55','g13','g13','g13','g6','g6','g7','g8','g8']
}
df3 = pd.DataFrame.from_dict(data)
df3
预期输出:
Out[270]:
org_id r_id Type_id grp_id
0 79 79 C g54
1 80 80 C g55
2 21 20 C g13
3 36 20 C g13
4 40 20 C g13
5 7 7 P g6
6 10 7 C g6
7 9 9 C g7
8 12 12 P g8
9 24 12 C g8
基于列(grp_id)上的组计数,如果该值等于one(1),则将type_id更改为“ C”
例如。 g54和g55仅出现一次,因此type_id ='C',g13和g6出现多次,所以我不更改该类型。谢谢。
答案 0 :(得分:1)
对所有重复项,将Series.where
与Series.duplicated
与 constructor(props){
super(props)
this.state = {
valueP: '',
quantity: '',
}}
...
<View style={Styles.type12Container}>
<View style={Styles.inputContainer}>
<Picker
value={this.state.valueP}
style={Styles.picker}
mode= "dropdown"
prompt= "XXX"
selectedValue = {this.state.valueP}
onValueChange = {(val) => { this.setState({valueP: val}}}>
<Picker.Item label="P 1" value="1" />
<Picker.Item label="P 2" value="2"/>
<Picker.Item label="P 3" value="3" />
</Picker>
</View>
<View style={Styles.inputContainer}>
<TextInput
value={this.state.quantity}
style={Styles.inputStyle}
onChangeText={(val) => this.setState({quantity: val})}
/>
</View>
<View style={Styles.button1Container}>
<TouchableOpacity
onPress={this.addConv}
style={Styles.buttonAdd}>
<Text style={Styles.button1Text}>Add</Text>
</TouchableOpacity>
</View>
<View style={Styles.output}>
<View>
<Text style={Styles.button1Text}>products and quantity items</Text>
</View>
</View>
</View>
一起使用掩码:
keep=False