Question

我有以下代码：

postgres=# create table foo (id text, name text);
CREATE TABLE
postgres=# insert into foo values (generate_series(95,105),'foo');
INSERT 0 11
postgres=# select * from foo where id > 100;
ERROR:  operator does not exist: text > integer
LINE 1: select * from foo where id > 100;
                                   ^
HINT:  No operator matches the given name and argument types. You might need to add explicit type casts.
postgres=# select * from foo where to_number(id,'99999') > 100;
 id  | name 
-----+------
 101 | foo
 102 | foo
 103 | foo
 104 | foo
 105 | foo
(5 rows)

但是我希望99999是postgres=# select * from foo where id::int > 100; id | name -----+------ 101 | foo 102 | foo 103 | foo 104 | foo 105 | foo (5 rows)。

目前，我阅读total_csv = pd.read_csv('total.csv',header=0).iloc[:,:] column28=total_csv ['28'] column27=total_csv ['27'] column26=total_csv ['26'] column25=total_csv ['25'] column24=total_csv ['24'] column23=total_csv ['23'] master_values=(column23,column24,column25,column26,column27,column28) In [68]:master_values Out[68]: (0 6867.488928 Name: 23, dtype: float64, 0 6960.779317 Name: 24, dtype: float64, 0 7007.540137 Name: 25, dtype: float64, 0 7031.11444 Name: 26, dtype: float64, 0 7127.469389 Name: 27, dtype: float64, 0 7408.207806 Name: 28, dtype: float64)的方式如下：

master_values

我怎样才能将(6867.488928,6960.779317,7007.540137,7031.11444,7127.469389,7408.207806)读为total_csv？

Answer 1

columnXX变量是否必要？

也许只是尝试以下操作： master_values = pd.read_csv（'total.csv'，header = 0）.iloc [0]

，如果您需要括号中所示的元组，可以这样做： master_values = tuple（pd.read_csv（'total.csv'，header = 0）.iloc [0]）

Answer 2

您可以尝试以下方法：

total_csv.to_numpy()[0][0].split('  ')[1:]

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2 个答案: