在基类中创建派生类的对象

时间:2019-11-21 19:02:02

标签: c++ inheritance

这是我的代码。我正在尝试从基类的派生类创建对象,但是它有一些错误。

#include <iostream>
#include<Windows.h>
#include <string>
#include <ctime>

using namespace std;

class PrgDevice {
private:
    tm startTime;
    tm stopTime;
    int choice;
    int choice1;
    char c;
public:
    int dateTime() {
        cout << "Enter start date and start time: ";
        cin >> startTime.tm_mday >> startTime.tm_mon >> startTime.tm_year >> startTime.tm_hour >> startTime.tm_min >> startTime.tm_sec;
        cout << "Enter stop date and stop time: ";
        cin >> stopTime.tm_mday >> stopTime.tm_mon >> stopTime.tm_year >> stopTime.tm_hour >> stopTime.tm_min >> stopTime.tm_sec;
    }

    void mainMenu() {
        while (choice != 3) {
            cout << "Main menu options:";
            cout << "      1. Select a device to program (contains a submenu)" << endl;
            cout << "      2. Display current status of all devices" << endl;
            cout << "      3. Exit" << endl;
            cout << "Enter your option => ";
            cin >> choice;

            if (choice == 1) {
                subMenu();
            }
            else if (choice == 2) {
                cout << choice;
            }
            else {

            }
        }
        system("pause");
    }
    void subMenu() {
        cout << "Select a device:" << endl;
        cout << "         1. PVR" << endl;
        cout << "         2. Camera DVR" << endl;
        cout << "         3. Oven" << endl;
        cout << "Enter your option => ";
        cin >> choice1;

        if (choice1 == 1) {
            PVR n1;
        }
        else if (choice1 == 2) {
            DVR n2;
        }
        else {
            Oven n3;
        }
    }
    void newDevice() {
        if (c == 'Y' || c == 'y') {
            subMenu();
        }
        else {
            mainMenu();
        }
    }
};

class PVR : public PrgDevice {
private:
    int channel;
public:
    PVR() {
        cout << "Select the channel ==> ";
        cin >> channel;
        cout << endl;
        dateTime();
        cout << endl;
        cout << "Another device to program Y/N ? => ";
        newDevice();
    }
};

class DVR : public PrgDevice {
private:
    string position;
public:
    DVR() {
        cout << "Select the position ==> ";
        getline(cin, position);
        cout << endl;
        dateTime();
        cout << endl;
        cout << "Another device to program Y/N ? => ";
        newDevice();
    }
};

class Oven : public PrgDevice {
private:
    string food;
public:
    Oven() {
        cout << "What do you want to bake? ==> ";
        getline(cin, food);
        cout << endl;
        dateTime();
        cout << endl;
        cout << "Another device to program Y/N ? => ";
        newDevice();
    }
};

int main() {
    PrgDevice obj1;
    obj1.mainMenu();



    system("pause");
    return 0;
}

以下是错误:

  

错误C2065:“ PVR”:未声明的标识符   错误C2146:语法错误:缺少';'在标识符“ n1”之前    错误C2065:“ n1”:未声明的标识符   错误C2065:“ DVR”:未声明的标识符   错误C2146:语法错误:缺少';'在标识符“ n2”之前    错误C2065:“ n2”:未声明的标识符   错误C2065:“烤箱”:未声明的标识符   错误C2146:语法错误:缺少';'在标识符“ n3”之前    错误C2065:“ n3”:未声明的标识符   1>完成的建筑项目“ Project1.vcxproj”-失败。   ===========构建:0成功,1失败,0最新,跳过0 ==========

请帮助我。谢谢。

2 个答案:

答案 0 :(得分:1)

目前还不清楚为什么在这里使用继承。本质上,三个对象PVR DVROven不需要从PrgDevice派生。一旦没有派生出来,您可以将它们移到PrgDevice之前,以便在那里使用它们。

class PVR {...
};
class DVR  {...
};
class Oven {...
};
class PrgDevice {...
};

由于PVR DVROven的构造函数都这样做

dateTime();
cout << endl;
cout << "Another device to program Y/N ? => ";
newDevice();

我们可以将其移至PrgDevice::submenu函数中。

void subMenu() { ...
  if (choice1 == 1) {
     PVR n1;
  }
  else if (choice1 == 2) {
     DVR n2;
  }
  else {
    Oven n3;
  }
  dateTime();
  cout << endl;
  cout << "Another device to program Y/N ? => ";
  newDevice();
}

但是,这并不能解决您的所有问题。您不断递归:

  • mainMenu呼叫subMenu
  • submenu呼叫newDevice
  • newDevice呼叫submenunewDevice

接下来需要修复。新设备实际上应该停留在submenu返回回到主菜单。为此,我们添加了do while循环

void submenu()
{
  do {
      cout << "Select a device:" << endl;
      ...
      cout << "Another device to program Y/N ? => ";

      cin >> c;
  }
  while(c == 'Y' || c == 'y');
}

我留下了一个看似工作的版本,其中带有datetime函数here的注释掉了

echo -e "1 1 1 y 2 2\n n 3"

它输出

Main menu options: 
      1. Select a device to program (contains a submenu)
      2. Display current status of all devices
      3. Exit
Enter your option => Select a device:
         1. PVR
         2. Camera DVR
         3. Oven
Enter your option => Select the channel ==> 

Another device to program Y/N ? => Select a device:
         1. PVR
         2. Camera DVR
         3. Oven
Enter your option => Select the position ==> 

Another device to program Y/N ? => Main menu options: 
      1. Select a device to program (contains a submenu)
      2. Display current status of all devices
      3. Exit
Enter your option => 

答案 1 :(得分:0)

在使用对象类型之前,需要先定义它们。与其将代码内联到类定义中,不如将它们分隔在代码的顶部(或包含在其中),然后当您真正开始使用它们时,编译器就会知道您在做什么。

class A {
    // Define stuff, but don't inline your methods
}

class B: public A {
    // Define stuff, but don't inline your methods
};

void A::subMenu() {
    // All your code
}