Question

很抱歉，其他帖子，有一个错误。

我的简化代码：

#test
import json

x = {}

x['x'] = {'y': 1, 'z': 0}

with open('x.json', 'w') as f:
    json.dump(x, f)

和

#test2
import json

f = open('x.json')
x = json.load(f)

while x['x']['y'] > 0:
    x['x']['z'] = x['x']['z'] + 1
    x['x']['y'] = x['x']['y'] - 1

    if x['x']['y'] == 0:
        print(x['x']['z'])
        n = input("Number: ")
        while n.isdigit() == False:
            print("Not a number")
            n = input("Number: ")

        if n.isdigit() == True:
            x['x']['y'] = int(n)
            with open('x.json', 'w') as f:
                json.dump(x, f)

我有两个代码，所以我不会用test覆盖test2的数字

这已经是我想要的，但是我对n = 4 和n = 5 的输出是：

1
Number: 4
5
Number: 5
10
Number:

依此类推...

但是，我希望代码完全退出，然后在不手动执行的情况下再次启动它。有点像：

1
Number: 4

代码重新启动

5
Number: 5

代码重新启动

5
Number: 10

，依此类推。谢谢：-）

Answer 1

如果我对您的理解正确，则必须创建两个单独的脚本

test1.py

#test
import json
import os
x = {}

x['x'] = {'y': 1, 'z': 0}

with open('x.json', 'w') as f:
    json.dump(x, f)

os.system('python test2.py') # this line will run the second script

test2.py

import json

f = open('x.json')
x = json.load(f)

while x['x']['y'] > 0:
    x['x']['z'] = x['x']['z'] + 1
    x['x']['y'] = x['x']['y'] - 1

    if x['x']['y'] == 0:
        print(x['x']['z'])
        n = input("Number: ")
        while n.isdigit() == False:
            print("Not a number")
            n = input("Number: ")

        if n.isdigit() == True:
            x['x']['y'] = int(n)
            with open('x.json', 'w') as f:
                json.dump(x, f)

是否有用于退出和重新输入脚本的命令？

1 个答案: