我有类似波纹管的数据,我想渲染它们。
假设我要为乘客的每次航班显示firstName
,address
,seatType
和flightId
。必须为每个乘客显示。我该如何实现?
已更新
[
{
"id": 1,
"firstName": "Smith",
"lastName": "John",
"address": [
"1 Street",
"YYY",
],
"flights": [
{
"flightId": 1,
"seatType": "oridinary"
},
{
}
]
},
{},
]
这是我的代码
render() {
const { data } = this.state;
return (
<div>
{" "}
{Object.keys(data).map((key, index) => (
<p key={index}>
{" "}
{key} {data[key].flights}
{data[key].flights.map(k => (
{data[key].flights[k]}
))}
</p>
))}
</div>
);
}
答案 0 :(得分:2)
我假设您正在寻找这样的东西:
return (
<div>
{
passengers.map(passenger => {
if (!passenger.id) { return null } /* + */
return (
<div key={passenger.id}>
<span>{passenger.firstName} {passenger.lastName}</span>
<div>
<span>Passenger's Flights</span>
{
passenger.flights && /* + */
Array.isArray(passenger.flights) && /* + */ passenger.flights.map(flight => {
if (flight.flightId) {
return (
<div key={flight.flightId}>
{flight.seatType}
</div>
)
}
return null
})
}
</div>
</div>
)
})
}
</div>
);
}
注意:请记住,不应将索引用作键。
编辑:您需要添加一个空/未定义的检查
答案 1 :(得分:0)
render() {
const { data } = this.state;
return (
<div>
{data.map((passenger, index) => (
<p key={index}>
{passenger.firstName} {passenger.address.join(' ')}
{passenger.flights.map(flight => (
<p>{flight.seatType} {flight.flightId}</p>
))}
</p>
))}
</div>
);
}
答案 2 :(得分:0)
render() {
const { data } = this.state;
return (
<div>
{data.map(({id, firstName, address, flights}) => (
<p key={id}>
<div>{firstName}</div>
<div>{address.join(', ')}</div>
{flights.map(f => (<div key={f.flightId}>{f.flightId}-{f.seatType}</div>))}
</p>
))}
</div>
);
}
不确定它是否可以编译,但这是这样的。另外,如果您有ID,请将其用作密钥。