我如何使用嵌套的<ul>
项目来处理具有未知数量的子项的菜单,如下例所示?
[
{
title: "Top level 1",
slug: "top-level-1",
children: [
{
title: "Sub level 1",
slug: "sub-level-1",
children: [
{
title: "Sub Sub Level 1"
slug: "sub-sub-level-1"
}
]
}
{
title: "Sub level 2",
slug: "sub-level-2"
}
]
},
{
title: "Top level 2",
slug: "top-level 2"
}
]
答案 0 :(得分:2)
您只需递归调用Menu组件,让其子组件显示并作为数据道具传递。
let data = [
{
title: "Top level 1",
slug: "top-level-1",
children: [
{
title: "Sub level 1",
slug: "sub-level-1",
children: [
{
title: "Sub Sub Level 1",
slug: "sub-sub-level-1",
children: [
{
title: "Sub Sub Level 2",
slug: "sub-sub-level-2"
}
]
}
]
},
{
title: "Sub level 2",
slug: "sub-level-2"
}
]
},
{
title: "Top level 2",
slug: "top-level 2"
}
];
const Menu = ({data}) => {
return (
<ul>
{data.map(m => {
return (<li>
{m.title}
{m.children && <Menu data={m.children} />}
</li>);
})}
</ul>
);
}
const App = () => (
<div style={styles}>
<Hello name="CodeSandbox" />
<h2>Start editing to see some magic happen {'\u2728'}</h2>
<Menu data={data} />
</div>
);
答案 1 :(得分:2)
您可以递归渲染具有可变深度的嵌套数据的组件。
示例代码段。
var data = [
{
title: "Top level 1",
slug: "top-level-1",
children: [
{
title: "Sub level 1",
slug: "sub-level-1",
children: [
{
title: "Sub Sub Level 1",
slug: "sub-sub-level-1"
}
]
},
{
title: "Sub level 2",
slug: "sub-level-2"
}
]
},
{
title: "Top level 2",
slug: "top-level 2"
}
]
const MyComponent = (props) => {
if(Array.isArray(props.collection)) {
return <ul>
{props.collection.map((data)=> {
return <li>
<ul>
<li>{data.title}</li>
<li>{data.slug}</li>
<li><MyComponent collection={data.children}/></li>
</ul>
</li>
})
}
</ul>
}
return null;
}
class App extends React.Component {
render() {
return (
<MyComponent collection={data}/>
)
}
}
ReactDOM.render(<App/>, document.getElementById('app'))
&#13;
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
<div id="app"></div>
&#13;
P.S。该代码段包含格式错误,但我相信您将能够纠正错误。片段是对方法的概念