骰子翻滚概率

Question

我正在尝试找出1个骰子骰中出现奇数的可能性。我知道这是3/6 = 1/2。 公式=可能的结果/总结果= 3个可能的结果/ 6个总结果= 1/2。 同样，如果我将相同的骰子掷出2倍，则概率= 1/2 * 1/2。 一旦生成随机数，我的代码就无法找到可能的总结果。感谢任何指针。

import random
# Determine sample space or total outcomes
N = [1,2,3]
dice_max = 6
outcomes = [] 

for i in range (len(N)):
    elem = N[i]
    if elem == 1:
        sample_outcomes = elem * dice_max
    else:
        sample_outcomes = dice_max ** elem
    outcomes.append(sample_outcomes)
    #print(outcomes)
    #print(sample_outcomes)    

# Determine if the dice roll is randomly 1,3,5 
    possible_outcomes = 0
    result = random.randint(1, 6)
# Determing possible outcomes
    if result == 1 or result ==3 or result ==5:
        possible_outcomes +=1
    print (possible_outcomes)