Question

Click here to see step 3 到目前为止，我认为第1步和第2步步入正轨，但是如果我可以改进它，请告诉我。对于第3步，我不知道如何显示所有20行（如果已保留或未保留）以及输入用户的名称。

reserveDict = {}



def reserve():

  global reserveDict


  tablenum = int(input("Enter a number: "))
  if tablenum not in reserveDict.keys():
    name = input("Table is avaiable, please enter your name: ")
    reserveDict[tablenum] = name 
  else:
    print("Table is unavaiable")



def remove():
  global tablenum

  tablenum = int(input("Enter the table number: "))





 del reserveDict[tablenum]

def report():
  global reserveDict



 count = len(reserveDict)






while(True):
 print("1- Reserve a Table")
 print("2- Clear Reservation")
 print("3- Report")
 print("0- Exit")

choice = int(input("Choose a option "))

if choice == 1:
    reserve()

elif choice == 2:
    remove()

Answer 1

我没有改进您的步骤1、2。我只是构建了步骤3和4。这是完整的代码。

reserveDict = {}



def reserve():

  global reserveDict
  tablenum = int(input("Enter a number: "))
  if tablenum not in reserveDict.keys():
    name = input("Table is avaiable, please enter your name: ")
    reserveDict[tablenum] = name 
  else:
    print("Table is unavaiable")



def remove():
  global tablenum
  tablenum = int(input("Enter the table number: "))
  del reserveDict[tablenum]

def report():
  global reserveDict
  for i in range(20):
      if i in reserveDict.keys():
          print(i,reserveDict[i])
      else:
          print(i,"available")







while(True):
    print("1- Reserve a Table")
    print("2- Clear Reservation")
    print("3- Report")
    print("0- Exit")

    choice = int(input("Choose a option "))

    if choice == 1:
        reserve()

    elif choice == 2:
        remove()
    elif choice == 3:
        report()
    elif choice == 0:
        exit()

我不知道如何显示此作业的第3步

1 个答案: