Question

有没有人知道如何在SQL Server中执行后打印SQL查询的输出？

select count(eo.equal_opps_id) as 'Age 40 - 49'
from dbo.app_equal_opps eo, dbo.app_status s
where eo.date_of_birth > DateAdd(yy,-49,getDate())
and eo.date_of_birth < DateAdd(yy,-39,getDate())
and eo.application_id = s.status_id
and s.job_reference_number = '33211016'
and s.submitted = 1

上面显示了一个SQL查询，但是，一旦执行它，我希望看到在以下部分创建的实际日期值

DateAdd(yy,-49,getDate())
DateAdd(yy,-39,getDate())

换句话说，一旦执行了查询，我可以打印SQL Query输出，以便显示类似这样的内容

select count(eo.equal_opps_id) as 'Age 40 - 49'
from dbo.app_equal_opps eo, dbo.app_status s
where eo.date_of_birth > '1962-05-04 13:00:00.000'
and eo.date_of_birth < '1972-05-04 13:00:00.000'
and eo.application_id = s.status_id
and s.job_reference_number = '33211016'
and s.submitted = 1

与往常一样，任何反馈都会非常感激。

谢谢大家。

Answer 1

将两个日期添加到您的选择列表中：

select 
   count(eo.equal_opps_id) as 'Age 40 - 49' 
  ,DateAdd(yy,-49,getDate()) as LesserDate
  ,DateAdd(yy,-39,getDate()) as GreaterDate
from 
  dbo.app_equal_opps eo, dbo.app_status s 
where 
  eo.date_of_birth > DateAdd(yy,-49,getDate()) 
  and eo.date_of_birth < DateAdd(yy,-39,getDate()) 
  and eo.application_id = s.status_id 
  and s.job_reference_number = '33211016' 
  and s.submitted = 1

Answer 2

我能想到的唯一方法就是凌乱。您可以将sql构建为字符串，然后使用内置函数中的exec执行它。

declare @sql as varchar(max)

select @sql = '
select count(eo.equal_opps_id) as ''Age 40 - 49''
from dbo.app_equal_opps eo, dbo.app_status s
where eo.date_of_birth > ' + ( select cast(DateAdd(yy,-49,getDate()) as varchar(100)) ) + '
and eo.date_of_birth < ' + ( select cast(DateAdd(yy,-39,getDate()) as varchar(100)) ) + '
and eo.application_id = s.status_id
and s.job_reference_number = ''33211016''
and s.submitted = 1'

print @sql
exec(@sql)

SQL Server：打印生成的SQL查询

2 个答案: