Question

我有3个1D列表。

repetitions= [2, 1, 1, 3, 1, 1, 1, 1, 2, 1]
start = [10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
end = [20, 30, 40, 50, 60, 70, 80, 90, 100, 110]

我想使用重复列表从 start [i] 到 end [i] 填充值为1的2D输出np.array。

例如，让我们假设我的输出数组的形状为（150,10），其中填充了零。

Output = [
         [0,0,0,0,0,0,0,0,0,0] #0
         [0,0,0,0,0,0,0,0,0,0] #1
         [0,0,0,0,0,0,0,0,0,0] #2
         [0,0,0,0,0,0,0,0,0,0] #3
         [0,0,0,0,0,0,0,0,0,0] #4
         [0,0,0,0,0,0,0,0,0,0] #5
         [0,0,0,0,0,0,0,0,0,0] #6
         [0,0,0,0,0,0,0,0,0,0] #7
         [0,0,0,0,0,0,0,0,0,0] #8
         [0,0,0,0,0,0,0,0,0,0] #9
         [0,0,0,0,0,0,0,0,0,0] #10
         [0,0,0,0,0,0,0,0,0,0] #11
         [0,0,0,0,0,0,0,0,0,0] #12
         [0,0,0,0,0,0,0,0,0,0] #13
         [0,0,0,0,0,0,0,0,0,0] #14
         ...
         ]

首先，我必须迭代重复列表以获取迭代开始列表和结束列表的次数，并获取行和列索引以填充输出数组。

例如，重复列表的第一列（索引为 0 的列）等于 2 ，那么我将必须迭代开始列表和结束列表 2 次并填充输出数组，首先，从行索引（ start [0] == 10 ）到行 end [0] == 20 在列索引索引0 （即重复列表中重复值2的索引）处的值为1。

然后从开始[1] 到结束[2] ，同时在索引0 处也使用值1。

第一次迭代的输出数组将如下所示：

Output = [
         [0,0,0,0,0,0,0,0,0,0] #0
         [0,0,0,0,0,0,0,0,0,0] #1
         [0,0,0,0,0,0,0,0,0,0] #2
         [0,0,0,0,0,0,0,0,0,0] #3
         [0,0,0,0,0,0,0,0,0,0] #4
         [0,0,0,0,0,0,0,0,0,0] #5
         [0,0,0,0,0,0,0,0,0,0] #6
         [0,0,0,0,0,0,0,0,0,0] #7
         [0,0,0,0,0,0,0,0,0,0] #8
         [0,0,0,0,0,0,0,0,0,0] #9
         [1,0,0,0,0,0,0,0,0,0] #10
         [1,0,0,0,0,0,0,0,0,0] #11
         [1,0,0,0,0,0,0,0,0,0] #12
         [1,0,0,0,0,0,0,0,0,0] #13
         [1,0,0,0,0,0,0,0,0,0] #14
         [1,0,0,0,0,0,0,0,0,0] #15
         [1,0,0,0,0,0,0,0,0,0] #16
         [1,0,0,0,0,0,0,0,0,0] #17
         [1,0,0,0,0,0,0,0,0,0] #18
         [1,0,0,0,0,0,0,0,0,0] #19
         [1,0,0,0,0,0,0,0,0,0] #20
         ...
         ]

然后，重复列表的第二列（具有索引1 的列）等于 1 ，那么我将必须迭代开始列表和结束列表 1 时间和填充输出数组，从行索引（ start [1] == 20 ）到列的 end [1] == 30 行索引索引1 （这是重复列表中重复值1的索引），值为1。依此类推。

第二次迭代的输出数组将如下所示：

Output = [
         ...
         [1,0,0,0,0,0,0,0,0,0] #10
         [0,0,0,0,0,0,0,0,0,0] #11
         [0,0,0,0,0,0,0,0,0,0] #12
         [0,0,0,0,0,0,0,0,0,0] #13
         [0,0,0,0,0,0,0,0,0,0] #14
         [0,0,0,0,0,0,0,0,0,0] #15
         [0,0,0,0,0,0,0,0,0,0] #16
         [0,0,0,0,0,0,0,0,0,0] #17
         [0,0,0,0,0,0,0,0,0,0] #18
         [0,0,0,0,0,0,0,0,0,0] #19
         [0,1,0,0,0,0,0,0,0,0] #20
         [0,1,0,0,0,0,0,0,0,0] #21
         [0,1,0,0,0,0,0,0,0,0] #22
         [0,1,0,0,0,0,0,0,0,0] #23
         [0,1,0,0,0,0,0,0,0,0] #24
         [0,1,0,0,0,0,0,0,0,0] #25
         [0,1,0,0,0,0,0,0,0,0] #26
         [0,1,0,0,0,0,0,0,0,0] #27
         [0,1,0,0,0,0,0,0,0,0] #28
         [0,1,0,0,0,0,0,0,0,0] #29
         [0,1,0,0,0,0,0,0,0,0] #30
         ...
         ]

这是我尝试过的，但我很困惑：

Output=np.zeros((150, 10))

for i in range(len(start)):
    for j in range(10):
        ms = repetions[i][j]
        for p in range(ms):
            Output[start[i]:end[i], p]=1

Python使用从索引到另一个的值填充数组

0 个答案: