Question

在我的情况下，我有一个字符串数组，我需要删除数组括号和双引号，如下所示，该如何实现？

我尝试了以下代码

let selectedTeamMemberID = membersData.filter{$0.isSelected}.map{$0.userid}
let intArray = selectedTeamMemberID.map { Int($0 ?? "")!}
print("\(intArray)")

预期产量

["1","2","3"] change to 1,2,3

Answer 1

尝试一下

您可以使用内置方法连接一个字符串数组

let selectedTeamMemberID = membersData.filter{$0.isSelected}.map{$0.userid}
let output = selectedTeamMemberID.joined(separator: ",")

Answer 2

如果您不想包括没有userId的对象，则也可以对该属性进行过滤并强制将其拆开。这样可以避免结果中出现“空”元素

let selected = membersData.filter{$0.isSelected && $0.userid != nil}.map {$0.userid!}.joined(separator: ",")

但是也许更有效和更清洁的解决方案是使用compactMap映射并过滤出零值

let selected = membersData.filter{$0.isSelected}.compactMap {$0.userid}.joined(separator: ",")

Answer 3

在打印数组时，它会打印字符串表示形式。

您需要遍历数组并打印内容

"scripts": {
    "start": "react-scripts start",
    "build": "webpack --mode production",
    "test": "react-scripts test --env=jsdom",
    "eject": "react-scripts eject"
},
"proxy": "http://url../v1",
"eslintConfig": {
    "extends": "react-app"
},

Answer 4

我们可以在数据映射后添加Joined

let selectedID = membersData.filter{$0.isSelected}.map{($0.userid ?? "")}.joined(separator: ",") // ["1","2","3"] to 1,2,3

Answer 5

您可以这样做：

selectedTeamMemberID.joined(separator: ",")

：）

快速删除数组括号和双引号

5 个答案: