如何从NSString中删除双引号和括号

Question

我在["658681","655917","655904"]中有一个字符串我希望以这种形式更改此字符串658681,655917,655904如何更改它？下面是我的字符串代码

- (IBAction)Searchbtn:(id)sender {

    NSData *data=[NSJSONSerialization dataWithJSONObject:getmessageIDArray options:kNilOptions error:nil];
    _finalIDStr=[[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
    NSLog(@"the final ID Str==%@",_finalIDStr);



}

Answer 1

这将在swift

中完成

var stringwithoutquotes = string1.stringByReplacingOccurrencesOfString("\"", withString: "")
var removebracket1 = stringwithoutquotes.stringByReplacingOccurrencesOfString("[", withString: "")
var removebracket2 = removebracket1.stringByReplacingOccurrencesOfString("]", withString: "")

或者你可以在一行中完成整个事情

var string2 = string.stringByReplacingOccurrencesOfString("\"", withString: "").stringByReplacingOccurrencesOfString("[", withString: "").stringByReplacingOccurrencesOfString("]", withString: "")

这是swift

中的另一个清洁选项

var string = "\"hello[]" // string starts as "hello[]
var badchar: NSCharacterSet = NSCharacterSet(charactersInString: "\"[]")
var cleanedstring: NSString = (string.componentsSeparatedByCharactersInSet(badchar) as NSArray).componentsJoinedByString("")
//cleanedstring prints as "hello"

斯威夫特3：

let string = "\"hello[]" // string starts as "hello[]
let badchar = CharacterSet(charactersIn: "\"[]")
let cleanedstring = string.components(separatedBy: badchar).joined()
//cleanedstring prints as "hello"

Answer 2

使用以下代码：

NSCharacterSet *unwantedChars = [NSCharacterSet characterSetWithCharactersInString:@"\"[]"];
NSString *requiredString = [[_finalIDStr componentsSeparatedByCharactersInSet:unwantedChars] componentsJoinedByString: @""];

从一行中删除字符串中的多个字符是一种高效且有效的方法..

Answer 3

Swift 4（String Array） 我想将String Array转换为String文本放在TextView中：

发件人
[＆＃34;马＆＃34;＆＃34;猫＆＃34;＆＃34;狗＆＃34;]

以
马
猫
狗

var stringArray = ["horse","cat","dog"]

var stringArrayCleaned = stringArray.description.replacingOccurrences(of: "\"", with: "").replacingOccurrences(of: ",", with: "\n").replacingOccurrences(of: "[", with: "").replacingOccurrences(of: "]", with: "").replacingOccurrences(of: " ", with: "")


print(stringArrayCleaned)

Answer 4

您可以尝试：

[[[_finalIDStr stringByReplacingOccurrencesOfString:@"\"" withString:@""] stringByReplacingOccurrencesOfString:@"[" withString:@""] stringByReplacingOccurrencesOfString:@"]" withString:@""];

Answer 5

NSString *str = ["658681","655917","655904"];
NSCharacterSet *cs = [NSCharacterSet characterSetWithCharactersInString:@"\"[]"];
str = [[string componentsSeparatedByCharactersInSet:cs] componentsJoinedByString:@""];