救命! - SQL - IF其他IF逻辑用于返回Containstable选择

时间:2009-02-25 18:48:10

标签: sql linq-to-sql full-text-search user-defined-functions

我正在尝试使用IF else如果内联表中的逻辑值为SQL的函数并返回基于该逻辑的containsstable。但我有IF Else IF块的语法问题。谢谢您的帮助。因为我不能参数化containsstable中的列,所以我不得不求助于使用if else语句。这是代码。感谢。

我正在

Msg 156,Level 15,State 1,Procedure FullTextSearch,第17行 关键字“IF”附近的语法不正确。

ALTER FUNCTION [dbo].[FullTextSearch] 
(       
    @Columns nvarchar(100), @SearchPhrase nvarchar(100)
)

RETURNS TABLE 
AS    
RETURN 


IF (@Columns='Title')
   BEGIN
   SELECT * 
        from projects as P inner join
        containstable(PROJECTS, Title, @SearchPhrase) as K 
        on P.project_id = K.[KEY]
   END

ELSE IF (@Columns='Project_Details')
   BEGIN
   SELECT * 
    from projects as P inner join
    containstable(PROJECTS, Project_Details, @SearchPhrase) as K 
    on P.project_id = K.[KEY]
   END

ELSE IF (@Columns='Contact_Info')
   BEGIN
   SELECT * 
    from projects as P inner join
    containstable(PROJECTS, Contact_Info, @SearchPhrase) as K 
    on P.project_id = K.[KEY]
   END

ELSE IF (@Columns='Project_Description')
   BEGIN
   SELECT * 
        from projects as P inner join
        containstable(PROJECTS, Project_Description, @SearchPhrase) as K 
        on P.project_id = K.[KEY]
   END

ELSE -- (@Columns='All')
   BEGIN
   SELECT * 
        from projects as P inner join
        containstable(PROJECTS, (Title, Project_Details, Contact_Info,     Project_Description), @SearchPhrase) as K 
        on P.project_id = K.[KEY]
   END

3 个答案:

答案 0 :(得分:2)

您收到此错误是因为您尝试在内联表值函数中使用多个语句。

内联表值函数必须包含单个SELECT语句,类似于:

CREATE FUNCTION dbo.MyInlineFunction (@MyParam INT)
RETURNS TABLE
AS
RETURN 
(
    SELECT first_column, second_column FROM ...
)

您的函数需要声明为多语句函数,语法类似于:

CREATE FUNCTION dbo.MyMultiStatementFunction (@MyParam INT)
RETURNS @MyTable TABLE 
(
    first_column INT, second_column VARCHAR(100)  -- etc
)
AS
BEGIN
    IF (@MyParam = 1)
        INSERT INTO @MyTable (...)
        SELECT ... FROM ...
    ELSE
        INSERT INTO @MyTable (...)
        SELECT ... FROM ...

    RETURN
END

答案 1 :(得分:0)

首先,你在第一个IF而不是=

上有==

哦,是的,我注意到你在ELSE的CONTAINSTABLE参数中列出了两次ProjectDetails

如果您正在搜索特定字段,可以使用以下语法:

WHERE Title LIKE '%'+ @Search +'%'
      OR ProjectDetails LIKE '%' + @Search + '%'
      OR ContactInfo LIKE '%' + @Search + '%')

(警告)此语法忽略任何索引。

您可以查看此blog以获取适用于索引的解决方案。它似乎有一个很好的解决方案。

答案 2 :(得分:0)

查看sql management studio的多语句功能模板,即菜单:View-> Template Explorer-创建多语句表值函数。

问题是多语句功能的语法不同。还要注意,正如jmein所说的那样,第一个if =。