Question

我需要得到比我更了解SQL的人的帮助...... 我正在尝试进行单个SP调用，使用IF THEN ELSE但仍然得到三个＆＃34;多部分标识符无法绑定＆＃34;消息。

页面可以由商家或集团赞助。在advertEntityType字段中，我有一个＆＃34; B＆＃34;或者＆＃34; G＆＃34;对于企业或团体。在advertEntityID字段中，我有businessID或groupID。

SELECT
   Advertisements.advertEntityType
  ,Advertisements.advertEntityID
FROM Advertisements
WHERE Advertisements.advertPageName = @pageName

IF (Advertisements.advertEntityType = 'G')

    SELECT
      Group.groupID
     ,Group.groupName
     ,Group.groupPhone
     ,Group.groupWebsite
     ,Group.groupLogoName
    FROM Group
    WHERE Group.groupID = Advertisements.advertEntityID

ELSE

    SELECT
      Business.businessID
     ,Business.businessName
     ,Business.businessWorkPhone
     ,Business.businessWebsite
     ,Business.businessLogoName
    FROM Business
    WHERE Business.businessID = Advertisements.advertEntityID

当我尝试执行时，我收到这些消息，我似乎无法理解......

Msg 4104, Level 16, State 1, Procedure Sponsor_s01, Line 36
The multi-part identifier "Advertisements.advertEntityType" could not be bound.
Msg 4104, Level 16, State 1, Procedure Sponsor_s01, Line 46
The multi-part identifier "Advertisements.advertEntityID" could not be bound.
Msg 4104, Level 16, State 1, Procedure Sponsor_s01, Line 58
The multi-part identifier "Advertisements.advertEntityID" could not be bound.

Answer 1

Advertisements.advertEntityType是表名和列名。如果要在if语句中使用它们，则需要将这些值分配给局部变量。如果我理解正确，你想根据第一个select语句中的条件进行评估。在这种情况下，您应该使用此类查询：

DECLARE @entityType int --assuming the type of Advertisements.advertEntityType is int
DECLARE @advertEntityID int  --assuming the type of Advertisements.advertEntityID is int

SELECT
    @entityType = Advertisements.advertEntityType,
    @advertEntityID = Advertisements.advertEntityID
FROM Advertisements
WHERE Advertisements.advertPageName = @pageName

IF (@entityType = 'G')
    SELECT
        Group.groupID
       ,Group.groupName
       ,Group.groupPhone
       ,Group.groupWebsite
       ,Group.groupLogoName
    FROM Group
    WHERE Group.groupID = @advertEntityID
ELSE
    SELECT
        Business.businessID
       ,Business.businessName
       ,Business.businessWorkPhone
       ,Business.businessWebsite
       ,Business.businessLogoName
    FROM Business
    WHERE Business.businessID = @advertEntityID

SQL帮助 - 如果那么

1 个答案: