我是SQl的新手,并尝试自己学习。
我将学习SQL中if和else语句的用法
这是我尝试使用的数据,if或else语句 在下表中,我希望根据年龄使用sql查询更新注释,假设年龄在22到25之间,评论“在毕业生”
Age: 26 to 27, comments " post graduate"
Age: 28 to 30, comments "working and single"
Age: 31 to 33, comments " middle level manager and married"
表名:人
personid lastname firstname age comments
1 Cardinal Tom 22
2 prabhu priya 33
3 bhandari abhijeet 24
4 Harry Bob 25
5 krishna anand 29
6 hari hara 31
7 ram hara 27
8 kulkarni manoj 35
9 joshi santosh 28
答案 0 :(得分:5)
尝试使用CASE声明
Select personid,lastname,firstname,age,
Case when age between 26 and 27 then 'post graduate'
when age between 28 and 30 then 'working and single'
when age between 31 and 33 then ' middle level manager and married'
Else 'Nil'
End comments
from persons
答案 1 :(得分:1)
我可能会使用CASE语句
像
这样的东西SELECT *,
CASE
WHEN age BETWEEN 22 AND 25
THEN 'under graduate'
WHEN age BETWEEN 26 AND 27
THEN 'post graduate'
WHEN age BETWEEN 28 AND 30
THEN 'working and single'
WHEN age BETWEEN 31 AND 33
THEN 'middle level manager and married'
ELSE 'TADA'
END Comment
FROM persons
答案 2 :(得分:1)
根据您的要求,我们不能使用if ... else语句。案例......当陈述最合适时。另外一件事我们无法在任何查询中使用if ... else(我的意思是在select,insert,update中)。
和你的
Select personid,lastname,firstname,age,
Case when age between 26 and 27 then 'post graduate'
Case when age between 28 and 30 then 'working and single'
Case when age between 31 and 33 then ' middle level manager and married'
Else 'Nil'
End comments
from persons
答案 3 :(得分:0)
在标准SQL中,您将使用CASE语句。
update persons
set comments = case when age between 22 and 25 then 'undergraduate'
when age between 26 and 27 then 'post graduate'
-- etc.
end;