Question

使用Pandas填写缺失数据的最佳方法是什么？我有一个访客列表，其中缺少退出时间或进入时间。

visitor entry            exit
A   16/02/2016 08:46    16/02/2016 09:01
A   16/02/2016 09:20    16/02/2016 17:24
A   17/02/2016 09:12    17/02/2016 09:42
A   17/02/2016 09:55    NaT
A   17/02/2016 12:42    17/02/2016 12:56
A   17/02/2016 13:02    17/02/2016 17:32
A   17/02/2016 17:44    17/02/2016 18:24
A   18/02/2016 07:59    18/02/2016 16:40
A   18/02/2016 16:53    NaT
A   NaT                 19/02/2016 09:11
A   19/02/2016 09:27    19/02/2016 11:26
A   19/02/2016 12:28    19/02/2016 17:12
A   20/02/2016 08:44    20/02/2016 08:58
A   20/02/2016 09:16    20/02/2016 17:21

Answer 1

您可以使用DataFrame.ffill + DataFrame.bfill 并在同一时间进入/退出：

df[['entry','exit']]=df[['entry','exit']].ffill(axis=1).bfill(axis=1)
print(df)
   visitor               entry                exit
0        A 2016-02-16 08:46:00 2016-02-16 09:01:00
1        A 2016-02-16 09:20:00 2016-02-16 17:24:00
2        A 2016-02-17 09:12:00 2016-02-17 09:42:00
3        A 2016-02-17 09:55:00 2016-02-17 09:55:00
4        A 2016-02-17 12:42:00 2016-02-17 12:56:00
5        A 2016-02-17 13:02:00 2016-02-17 17:32:00
6        A 2016-02-17 17:44:00 2016-02-17 18:24:00
7        A 2016-02-18 07:59:00 2016-02-18 16:40:00
8        A 2016-02-18 16:53:00 2016-02-18 16:53:00
9        A 2016-02-19 09:11:00 2016-02-19 09:11:00
10       A 2016-02-19 09:27:00 2016-02-19 11:26:00
11       A 2016-02-19 12:28:00 2016-02-19 17:12:00
12       A 2016-02-20 08:44:00 2016-02-20 08:58:00
13       A 2016-02-20 09:16:00 2016-02-20 17:21:00

编辑

DataFrame.notna + DataFrame.all执行boolean indexing来过滤NaT值的ros以便计算diff的均值

#filtering valid data
df_valid=df[df.notna().all(axis=1)]
#Calculating diff
time_dif=df_valid[['entry','exit']].diff(axis=1).exit
print(time_dif)

0    00:15:00
1    08:04:00
2    00:30:00
4    00:14:00
5    04:30:00
6    00:40:00
7    08:41:00
10   01:59:00
11   04:44:00
12   00:14:00
13   08:05:00
Name: exit, dtype: timedelta64[ns]

#Calculatin mean        
time_dif_mean=time_dif.mean()
print('This is the mean of time in: ', time_dif_mean)

This is the mean of time in:  0 days 03:26:54.545454

用平均值填充错误价值

#roud to seconds( optional)
time_dif_mean_round_second=time_dif_mean.round('s')

df['entry'].fillna(df['exit']-time_dif_mean_round_second,inplace=True)
df['exit'].fillna(df['entry']+time_dif_mean_round_second,inplace=True)
print(df)

输出：

   visitor               entry                exit
0        A 2016-02-16 08:46:00 2016-02-16 09:01:00
1        A 2016-02-16 09:20:00 2016-02-16 17:24:00
2        A 2016-02-17 09:12:00 2016-02-17 09:42:00
3        A 2016-02-17 09:55:00 2016-02-17 13:21:55
4        A 2016-02-17 12:42:00 2016-02-17 12:56:00
5        A 2016-02-17 13:02:00 2016-02-17 17:32:00
6        A 2016-02-17 17:44:00 2016-02-17 18:24:00
7        A 2016-02-18 07:59:00 2016-02-18 16:40:00
8        A 2016-02-18 16:53:00 2016-02-18 20:19:55
9        A 2016-02-19 05:44:05 2016-02-19 09:11:00
10       A 2016-02-19 09:27:00 2016-02-19 11:26:00
11       A 2016-02-19 12:28:00 2016-02-19 17:12:00
12       A 2016-02-20 08:44:00 2016-02-20 08:58:00
13       A 2016-02-20 09:16:00 2016-02-20 17:21:00

使用熊猫填写丢失的数据

1 个答案: