Question

我想计算PL中每个团队的得分

我有两个桌子

T1

---------------------
TEAM ID || TEAM NAME
---------------------
01      || Liverpool
02      || Man City
---------------------

例如t2时

----------------------------------------------------------------
MATCH ID || HOME TEAM || AWAY TEAM || HOME GOALS || AWAY GOALS|
-----------------------------------------------------------------
30       || Liverpool || Man City  || 1          || 0 
-----------------------------------------------------------------

计算积分现在，对于每场比赛，如果一个球队的进球数大于他赢得的另一支球队，他得到3分，而失败者得到0分但是如果每个人都达到相同的目标数，甚至每个人只有1分。

新表格应该是这样

-----------------------------------
Team ID || Team Name || Team Points
------------------------------------
01      || Liverpool || 28
02      || Man City  || 22
------------------------------------

Answer 1

加入表并使用条件聚合：

select t1.teamid, t1.teamname,
  sum(
    case sign((homegoals - awaygoals) * case when t1.teamname = t2.hometeam then 1 else -1 end)
      when 1 then 3
      when 0 then 1
      when -1 then 0
    end
  ) teampoints
from t1 inner join t2
on t1.teamname in (t2.hometeam, t2.awayteam)
group by t1.teamid, t1.teamname

请参见demo。

Answer 2

我建议横向连接：

select t1.team_id, t1.team_name, sum(v.goals),
       sum(case when goals > other_goals then 3 
                when goals = other_goals then 1
                else 0
           end) as points
from t2 cross join lateral
     (values (t2.home_team, t2.home_goals,  t2.away_goals),
             (t2.away_team, t2.away_goals, t2.home_goals)
     ) v(team, goals, other_goals) join
     t1
     on v.team = t1.team_id
group by t1.team_id, t1.team_name;

Answer 3

您可以加入表并进行条件求和：

select
    t1.team_id,
    t1.team_name,
    sum(
        case 
            when t2.home_goals = t2.away_goals then 1
            when 
                ( t1.team_name = t2.home_team and t2.home_goals > t2.away_team)
                or (t1.team_name = t2.away_team and t2.away_goals > t2.home_team)
                then 3
            else 0 
        end
    ) team_points
from t1
inner join t2 on t1.team_name in (t2.home_team, t2.away_team)
group by t1.team_id, t1.team_name

在sum()中，case表达式检查游戏的结果并根据需要分配点数（获胜游戏为3点，平局为1点，亏损为0点）。

注意：正如评论中所述，您应该修改架构以将团队的id个而不是其名称存储在得分表中。

Answer 4

现在，那

SELECT t1.teamid,
        t1.teamname,
        SUM (CASE   WHEN    t1.teamname = t2.hometeam
                            AND     t2.homegoals > t2.awaygoals THEN    3
                    WHEN    t1.teamname =   t2.awayteam
                            AND     t2.homegoals < t2.awaygoals THEN    3
                    WHEN    t1.teamname IN (t2.hometeam, t2.awayteam)
                            AND     t2.homegoals = t2.awaygoals THEN    1
                    ELSE    0
                    END
             )AS    "Team Points"

FROM    t1
        INNER JOIN
        t2
        ON
        t1.teamname IN (t2.hometeam, t2.awayteam)

GROUP BY t1.teamid,
        t1.teamname

这里是Demo

SQL复杂条件聚合

4 个答案: