我正在尝试创建一个表,以将文本文件中的巨大数据库分隔为username:email而不是整个用户:email:hash:etc
我有这个:
>>>CREATE TABLE `database`(
`UserGUID` varchar(40) CHARACTER SET latin1 NOT NULL,
`UserName` varchar(80) CHARACTER SET utf8 NOT NULL,
`Email` varchar(128) CHARACTER SET latin1 NOT NULL,
`Password` varchar(128) CHARACTER SET latin1 NOT NULL,
`Salt` varchar(128) CHARACTER SET latin1 NOT NULL,
`Strikes` int(10) unsigned NOT NULL DEFAULT '0',
`Locked` tinyint(1) unsigned NOT NULL DEFAULT '0',
`Deleted` tinyint(1) unsigned NOT NULL DEFAULT '0',
`CreatedDate` datetime NOT NULL,
`UpdatedDate` datetime DEFAULT NULL,
`DeletedDate` datetime DEFAULT NULL,
`CreatedBy` varchar(40) CHARACTER SET latin1 NOT NULL DEFAULT 'System',
`UpdatedBy` varchar(40) CHARACTER SET latin1 DEFAULT NULL,
`DeletedBy` varchar(40) CHARACTER SET latin1 DEFAULT NULL,
`EmailAuthenticated` tinyint(1) unsigned NOT NULL DEFAULT '0',
`FollowID` int(10) unsigned DEFAULT NULL,
`DefaultLocationID` int(10) unsigned DEFAULT NULL,
`birthDay` int(10) unsigned DEFAULT NULL,
`birthMonth` int(10) unsigned DEFAULT NULL,
`birthYear` int(10) unsigned DEFAULT NULL,
`BirthDate` datetime DEFAULT NULL,
`EmailAuthKey` varchar(45) COLLATE latin1_general_ci DEFAULT NULL,
`CurrentCrowns` int(11) NOT NULL DEFAULT '0',
`CurrentCardpoints` int(11) NOT NULL DEFAULT '0',
`LastFreeCrowns` datetime DEFAULT NULL,
`plaintextpassword` varchar(500) COLLATE latin1_general_ci DEFAULT NULL,
`LastAuthEmail` datetime DEFAULT NULL,
`premiumcards` int(11) DEFAULT NULL,
`steamid` varchar(80) COLLATE latin1_general_ci DEFAULT NULL,
`ExternalPromotionID` varchar(45) COLLATE latin1_general_ci DEFAULT NULL,
`culture` varchar(40) COLLATE latin1_general_ci DEFAULT NULL,
PRIMARY KEY (`UserGUID`) USING BTREE,
UNIQUE KEY `Username` (`UserName`),
UNIQUE KEY `Email` (`Email`),
UNIQUE KEY `Follow` (`FollowID`) USING BTREE,
KEY `EmailAuthenticated` (`EmailAuthenticated`),
KEY `SteamID` (`steamid`),
KEY `authkey` (`EmailAuthKey`),
KEY `IX_CreatedDate` (`CreatedDate`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci;
我一直收到此错误:错误:“ CHARACTER”附近:语法错误
帮助?