我正在尝试在我的应用中创建私人聊天,但是当我尝试创建表时出现此错误:
org.postgresql.util.PSQLException:错误:“ 7”或附近的语法错误 位置:14
代码:
public static String checkIfChatExists(String code, String friend) throws SQLException {
String i = LoginManager.checkCode(code);
if(i.equals("code-not-exists")) {
return "invalid-code";
}
ResultSet rs = conn.prepareStatement("SELECT * FROM pwchats").executeQuery();
while (rs.next()) {
if(rs.getString("user1").equals(i) && rs.getString("user2").equals(friend) || rs.getString("user1").equals(friend) && rs.getString("user2").equals(i)) {
return "exists";
}
}
PreparedStatement pre = conn.prepareStatement("INSERT INTO pwchats(user1, user2) VALUES(?, ?)");
pre.setString(1, i);
pre.setString(2, friend);
pre.execute();
PreparedStatement getChatId = conn.prepareStatement("SELECT * FROM pwchats WHERE user1 = ? AND user2 = ?;");
getChatId.setString(1, i);
getChatId.setString(2, friend);
ResultSet rss = getChatId.executeQuery();
while (rss.next()) {
PreparedStatement chat = conn.prepareStatement("CREATE TABLE " + rss.getInt("id") + "chat (username text NOT NULL, created_at timestamp with time zone NOT NULL DEFAULT now(), avatar text NOT NULL, message text NOT NULL, id serial NOT NULL);");
chat.execute(); //ERROR
return "done";
}
return "wat";
}
答案 0 :(得分:1)
您看到的错误可能来自那里:
preparedStatement chat = conn.prepareStatement("CREATE TABLE " + rss.getInt("id") + "chat (...);");
通常在SQL中,表名不能以数字开头。如果您要用双引号将表名括起来,则Postgres仍然允许,但是您每次查询时都需要对表名用双引号,这可能很麻烦。
一种解决方案是将数字放在表名的末尾,例如:
preparedStatement chat = conn.prepareStatement("CREATE TABLE chat" + rss.getInt("id") + " (...);");
create table 7chat(x int);
ERROR: syntax error at or near "7" LINE 1: create table 7chat(x int); ^
create table "7chat"(x int);
-- works
create table chat7(x int);
--works