Question

我正在尝试将JSON文件转换为CSV文件，但是当我运行构建时，它仅返回2行标题和第一个条目。

不确定发生了什么事，我尝试了几种不同的变体，但似乎没有任何效果，不确定是因为文件太大还是不超过6百万行...

import json
import csv


with open('result.json') as jsonfile:
data=jsonfile.read()

#ParseFile 
jsonobj = json.loads(data)

keylist = []
for key in jsonobj[0]:
keylist.append(key)

f = csv.writer(open("test-kyle.csv", "w"))
f.writerow(keylist)

for record in jsonobj:
currentrecord = []

for key in keylist:
    currentrecord.append(record[key])

f.writerow(currentrecord)

这是示例JSON文件：

[
    {
        "text": "<@U48TMD5QS> has joined the channel", 
        "ts": "1491388552.433852"
    }, 
    {
        "text": "*Channel: failed_signup* \nPhone number 123218736 failed to sign up on UGANDA", 
        "ts": "1491477391.593892"
    }, 
    {
        "text": "*Channel: failed_signup* \nPhone number 723880908 failed to sign up on UGANDA", 
        "ts": "1491477392.594092"
    }, 
    {
        "text": "*Channel: failed_signup* \nPhone number 723880908 failed to sign up on UGANDA", 
        "ts": "1491477393.594269"
    }, 
    {
        "text": "*Channel: failed_signup* \nPhone number 723880666 failed to sign up on UGANDA", 
        "ts": "1491477393.594395"
    }, 
    {
        "text": "*Channel: IT_ALERTS_GMAIL* \n[kve-t460] Failed to complete import cycle", 
        "ts": "1491477394.594630"
    }, 
    {
        "text": "*Channel: failed_signup* \nPhone number abcdefg failed to sign up on UGANDA", 
        "ts": "1491477434.604899"
    }, 
    {
        "text": "<@U1Y9UJD8V> has joined the channel", 
        "ts": "1493358499.130025"
    }
]

Answer 1

您的缩进被弄乱了很多。请小心，否则您的代码会起作用：

import json
import csv


with open('result.json') as jsonfile:
    data=jsonfile.read()

#ParseFile 
jsonobj = json.loads(data)

keylist = []
for key in jsonobj[0]:
    keylist.append(key)

f = csv.writer(open("test-kyle.csv", "w"))
f.writerow(keylist)

for record in jsonobj:
    currentrecord = []

    for key in keylist:
        currentrecord.append(record[key])

    f.writerow(currentrecord)

Answer 2

您需要更正for循环

for key in jsonobj:
    keylist.append(key)

Answer 3

检查代码上两个for循环的缩进！

Answer 4

Python需要4个空格用于缩进。如果您的代码未缩进，则您的keyList为空，它将跳过循环

for key in jsonobj[0]:
keylist.append(key)

Python'For Loop'不循环json

4 个答案: