Question

我正在尝试在python中创建一个CD密钥生成器，我正在生成四个块的密钥，每个长4个数字。我正在使用for循环从所有字母数字字符列表中生成字符，并将它们附加到字符串@import './../your_file_path/your_file_name.css';。

chunk1

# 4 digits to be generated for i in range(0, 4): chunk1 = "" # Choose randomly whether the next character will be a letter or digit uld = randint(0, 1) if uld == 0: character = 'letters' # Randomly choose a letter from all upper- and lowercase letters selector = randint(0, 51) elif uld == 1: character = 'digits' # Randomly choose a digit from 0-9 selector = randint(0, 9) # Set `chunk1` equal to itself and append the selected digit chunk1 = chunk1 + charset[character][selector] # References the `charset` dictionary是一个包含两个键的字典，一个用于大写和小写字母，另一个用于0-9的数字

charset

问题是charset = { 'letters': 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz', 'digits': '0123456789' }循环不生成4个字符，而只是一个，我似乎无法弄清楚原因。我可能会遗漏一些相当明显的东西。

Answer 1

每次迭代都会覆盖

chunk1。

相反，您应该将值存储在列表中。您也不需要所有这些字符串连接

output = []

for i in range(0, 4):
    # Choose randomly whether the next character will be a letter or digit
    uld = randint(0, 1)

    if uld == 0:
        character = 'letters'
        # Randomly choose a letter from all upper- and lowercase letters
        selector = randint(0, 51)

     elif uld == 1:
        character = 'digits'
        # Randomly choose a digit from 0-9
        selector = randint(0, 9)

    output.append(charset[character][selector])

print(''.join(output))

Answer 2

chunk1 = ""你可以将它移到外面进行循环。

Answer 3

问题是，你在循环中说chunk1 = ""。这意味着，每次循环运行时都将变量重置为“”。只需将它放在循环之外，它就可以正常工作：https://repl.it/Nlkj/0

For循环不循环

3 个答案: