Question

我需要构建一个函数，该函数将数字的单词表示形式作为输入并将其转换为数字。 one => 1，threethousandsixtyhundreadtwo => 3602等。我有数字(999,999)的上限，并且我已经做过反向功能。我也有将要使用的所有单词。到目前为止，当数字的不同部分之间没有空格或类似内容时，我仍然坚持如何分隔数字的每个部分。

在python中执行此操作。我没有找到使用find()的合理方法。

Answer 1

使用此代码：

def int2word(number):
    def num2word(num):
        n = ["one",
              "two",
              "three",
              "four",#lists
              "five",
              "six",
              "seven",
              "eight",
              "nine",
              "ten",
              "eleven",
              "twelve",
              "thirteen",
              "fourteen",
              "fifteen",
              "sixteen",
              "seventeen",
              "eighteen",
              "nineteen"]
        ten = [ "twenty",
                 "thirty",
                 "forty",
                 "fifty",
                 "sixty",
                 "seventy",
                 "eighty",
                 "ninety",
                 ]
        if num == 0:
            return ""
        elif num in range(1, 19):#for nos 0 - 19
            return  (n[num-1])
        elif num in range(20,99) and num%10 == 0:#for nos 20 - 99 that are multiples of ten
            return (ten[num//10 - 2])
        elif num in range(20,99)and num%10 > 0:
            return (ten[num//10-2] +"-"+ n[num%10-1])
    result = ""
    if  number == 0:
        result = "zero"
    else:
        c = number // 10000000
        if c !=  0:
            crores = num2word(c)
            result += crores + " crore "
        l = number % 10000000
        if l//100000 != 0:
            lakh = num2word(l//100000)
            result += lakh + " lakh "
        th = number%100000
        if th//1000 != 0:
            thos = num2word(th//1000)
            result += thos + " thousand "
        h = number%1000
        if h//100 != 0:
            huns = num2word(h//100)
            result += huns + " hundred "
        t = h % 100
        if t != 0:
            tens = num2word(t)
            result += tens
    return result

将数字从单词转换为数字

1 个答案: