我的cs类的这个作业的目标是在字符串中搜索数字并将其更改为书面形式
ex：4 -> four
这是一项相对简单的任务。但是我有两个问题：
1）由于我当前的代码，如果我转换了一串“8”并尝试将其设为“8”，它将无效，因为它是比字符串的当前长度长。
2）通过字符串连续处理多个数字char。我有点想通了。如果您使用某些Strings运行我所拥有的功能。我们应该用连字符分隔多个数字字符。
这是我的代码：
public class NumberConversion {
/**
* * Class Constants **
*/
/**
* * Class Variables **
*/
/* No class variables are needed due to the applet not having a state.
All it does is simply convert. */
/**
* * Class Arrays **
*/
char numberChar[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
String numbers[] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
/**
* * Accessor Methods **
*/
/**
* * Transformer/Mutator Methods **
*/
public void writeNumber(String phrase) {
/**
* Local Variables *
*/
String newPhrase = "";
int j = 0;
int k = 0;
phrase = phrase.trim();
/**
* * Counts through the length of phrase **
*/
for (int i = 0; i < phrase.length(); i++) {
/**
* * If the current char is a number char, enter the next repitition
* structure **
*/
int l = i + 1;
if (isNumber(phrase.charAt(i)) && isNumber(phrase.charAt(i + 1))) {
boolean searchArray = true;
do {
if (numberChar[ j] == phrase.charAt(i)) {
searchArray = false;
}
j++;
} while (searchArray && j < numberChar.length);
phrase = phrase.replace(Character.toString(phrase.charAt(i)), numbers[ j - 1] + "-"); //error HERE
}
if (isNumber(phrase.charAt(i))) {
boolean searchArray = true;
do {
/**
* * Counts through numberChar array to see which char was
* found in the phrase. Stops when found **
*/
if (numberChar[ k] == phrase.charAt(i)) {
searchArray = false;
}
k++;
} while (searchArray && k <= numberChar.length);
/**
* * Changes char to string and replaces it with the matching
* String numbers array element **
*/
phrase = phrase.replace(Character.toString(phrase.charAt(i)), numbers[ k - 1]);
}
phrase = phrase.replace("- ", " ");
}
System.out.println(phrase); // Prints the changed phrase.
}
/**
* * Helper Methods **
*/
/**
* * Observer Methods **
*/
public boolean isNumber(char input) {
boolean isNumber = false; // Initially fails
for (int i = 0; i < numberChar.length; i++) {
/**
* * If input matches a number char, method returns true **
*/
if (input == numberChar[ i]) {
isNumber = true;
}
}
return isNumber;
}
}
答案 0 :(得分：0)
不要替换当前字符串中的数字，创建新字符串，并继续追加它。然后，您可以避免许多不必要的验证。
List<Char> myNumberChar = Arrays.asList(numberChar);
List<Char> myNumbers = Arrays.asList(numbers);
StringBuilder mySB = new StringBuilder();
//String myResultString = ""; // If you don't want to use StringBuilder
for (int i = 0; i < phrase.length(); i++) {
mySB.append(myNumbers.get(myNumberChar.getIndexOf(phrase.charAt(i)))+"-");
//myResultString = myResultString + myNumbers.get(myNumberChar.getIndexOf(phrase.charAt(i)))+"-"; //Again, for no StringBuilder case
}
String myResult = mySB.toString();
// No need to do the above in no StringBuilder case, just use myResultString in place of myResult
System.out.println(myResult.subString(0, myResult.length - 1)); // removed the last hyphen
答案 1 :(得分：0)
我会使用String.replace
for(int i = 0; i < 10; i++) {
str = str.replace(numberChar[i] + "", numbers[i]);
}
答案 2 :(得分：0)
public class NumberConversion
{
/*** Class Variables ***/
/* No class variables are needed due to the applet not having a state.
All it does is simply convert. */
/*** Class Arrays ***/
char numberChar [] = {'0'，'1'，'2'，'3'，'4'， '5'，'6'，'7'，'8'，'9'};
String numberWord [] = {“zero”，“one”，“two”，“three”，“four”， “五”，“六”，“七”，“八”，“九”};
/*** Transformer/Mutator Methods ***/
public String writeNumber（String phrase） { / **局部变量** /
phrase = phrase.trim();
/*** Counts through the length of phrase ***/
for ( int i = 0; i < phrase.length(); i++ )
{
/*** If current char is a number, count through the array
that contains the number chars until the one needed is
found. ***/
if ( isNumber( phrase.charAt( i ) ) )
{
boolean keepSearching = true;
int j = 0;
do
{
if ( numberChar[ j ] == phrase.charAt( i ) )
keepSearching = false;
else
j++; // Increments j if char doesn't match array element
} while ( keepSearching && j < numberChar.length );
/*** Replaces the current char with the corresponding String
word from the other number array. ***/
phrase = phrase.replace( Character.toString(
phrase.charAt( i ) ) ,
numberWord[ j ] + "-" );
}
}
/*** Gets rid of dashes from unwanted places ***/
phrase = phrase.replaceAll( "- " , " " );
phrase = phrase.replaceAll( "-," , ", " );
phrase = phrase.replace( "-." , "." );
if ( phrase.charAt( phrase.length() - 1 ) == '-' )
phrase = phrase.substring( 0 , phrase.length() - 1 );
return phrase;
}
/*** Observer Methods ***/
public boolean isNumber（char input） { boolean isNumber = false; //最初失败
for ( int i = 0; i < numberChar.length; i++ )
{
/*** If input matches a number char, method returns true ***/
if ( input == numberChar[ i ] )
isNumber = true;
}
return isNumber;
}