Question

我有嵌套列表（（“ H”“ E”“ L”“ L”“ O”）（“ T”“ H”“ I”“ S”）（“ I”“ S”）（“ A “）（” T“” E“” S“” T“）））我想使用替代将列表中的每个字符串替换为另一个字符串，但是它不起作用我的代码是：

(substitute "H" "W" paragraph)

段落是嵌套列表的名称。

Answer 1

使用SUBST：

struct GameView: View { 
    @State var locationManager: LocationManager 


    var body: some View { 
        MapView(locationManager: $locationManager)
    }
}

struct MapView: UIViewRepresentable {

    @Binding var locationManager: LocationManager

   func makeUIView(context: Context) -> GMSMapView{ ... }

   func updateUIView(_ mapView: GMSMapView, context: Context) { ... }

}

class LocationManager: NSObject, CLLocationManagerDelegate, ObservableObject {

    var didChange = PassthroughSubject<LocationManager, Never>()

    var lastKnownLocation: CLLocation {
        didSet {


            // Propagate the update to the observers.
            didChange.send(self)
            print("Finished propagating lastKnownLocation to the observers.")
        }
    }

    ...

}

如果您需要修改列表，请使用CompletableFuture<List<String>> completableFuture = CompletableFuture.supplyAsync(() -> fetch.andThen(log).apply(url1)) .thenCombine(CompletableFuture.supplyAsync(() -> fetch.andThen(log).apply(url2)), //.thenCombine(CompletableFuture.supplyAsync(() -> fetch.andThen(log).apply(url3)), (s1, s2) -> List.of(s1,s2)); //(s1, s2, s3) -> List.of(s1, s2, s3));并将结果分配回原始变量：

(setq new-list (subst "W" "H" old-list :test #'string=))

在commonlisp的嵌套列表中替换字符串

1 个答案: