Question

我正在尝试编译以下代码：

make.

nextState是一个函数，states-list是一个列表，两者都是定义的。我得到了＆＃34;未定义的对state-list＆＃34;的引用。我不知道自己做错了什么。任何帮助将不胜感激

Answer 1

将严重的骆驼案件重命名为lisp案例我还剩下这个。

(defun next-states (st)
  "generate all possible states"
  (loop :for action :in (possible-actions)
        :for aux := (next-state st action) :then (next-state st action)
        :when (not (member aux states-list :test #'equalp))
          :collect aux :into states-list
        :finally (return states-list)))

这里的测试就是我所拥有的：

(defun possible-actions ()
  "have duplicates to see not member in action"
  '(0 1 3 3 4))

(defun next-state (st action)
  "Simple version for test"
  (+ st action))

(next-states 3) ; ==> (3 4 6 7)

获取未定义的引用commonLISP中的函数

1 个答案: