Question

有一个可变的LiveData Holding 2数组“ deal”和“ category”，我需要在不同的适配器中对此进行解析。

有没有办法将1个可变的实时数据转换为2个数组，然后将它们解析为两个不同的适配器

假设存在MutableVariable名称se

private lateinit var mHomePojo: MutableLiveData<List<HomePojo>>

解析Json如下

 {
   "status": 0,
   "response": "success",
   "category": [
     {
       "categoryName": "demo",
       "categoryDesc": "demo"
     },
     {
       "categoryName": "demo1",
       "categoryDesc": "demo"
     }
   ],
   "deal": [
     {
       "dealImg": "https://aiotechnology.in/Aditechweb/upload/153102117.jpg",
       "dealDesc": "gd",
       "dealStartDate": "2019-10-18",
       "dealEndDate": "2019-10-19"
     }
   ]
 }

有什么方法可以将private lateinit var mHomePojo: MutableLiveData<List<HomePojo>>解析为lateinit var mDealModel: MutableLiveData<List<DealModel>>并 lateinit var mCategoryModel: MutableLiveData<List<CategoryModel>>

我是MVVM的新手，请帮助

Answer 1

我认为Transformations可以帮助您将家庭实时数据分离为具有指定属性的两个单独的livedata对象。下面是这段代码。（注意：例如，未使用lateinit var）

private val homeLiveData: LiveData<HomePojo> = MutableLiveData<HomePojo>()

//Category Live data
private val categoryPojo = Transformations.map(homeLiveData) {
    it.category
}

//Deal live data
private val dealPojo = Transformations.map(homeLiveData) {
    it.deal
}

data class HomePojo(
   /*-- Other fields --*/
   val category: List<CategoryPojo>? = null,
   val deal: List<DealPojo>? = null)


data class CategoryPojo(
    val categoryName: String? = null,
    val categoryDesc: String? = null)

data class DealPojo(
    val dealImg: String? = null,
    val dealDesc: String? = null,
    val dealStartDate: String? = null,
    val dealEndDate: String? = null)

将可变实时数据解析为Kotlin中的阵列

1 个答案: