Question

亲爱的，我在使用JPQL查询时遇到问题，当我使用IN和List（Long）时遇到错误，但并非总是如此

this is the model （这是用于查看关系的最小模型，没有所有列）

如果我在mi repo中执行此查询，效果很好：

@Query(value = "SELECT a FROM Artist a WHERE a.idArtist IN(SELECT a.idArtist FROM ArtistStyle x "
            + "INNER JOIN x.style s " 
            + "INNER JOIN x.artist a " 
            + "WHERE s.idStyle IN (:arrayStyles))")
    public List<Artist> FilterArtistWithStyles(List<Long> arrayStyles);

但是如果我执行此查询，我会得到错误：

@Query(value = "SELECT a FROM Artist a WHERE a.idArtist IN(SELECT a.idArtist FROM ArtistStyle x "
            + "INNER JOIN x.style s " 
            + "INNER JOIN x.artist a " 
            + "INNER JOIN a.country c " 
            + "INNER JOIN a.aal1 a1 "
            + "INNER JOIN a.aal2 a2 " 
            + "INNER JOIN a.aal3 a3 " 
            + "WHERE (:arrayStyles IS NULL OR s.idStyle IN (:arrayStyles)) "
            + "AND (:name IS NULL OR a.name like %:name%)" + "AND (:gender IS NULL OR a.gender = :gender) "
            + "AND (:experienceFrom IS NULL OR a.workStartYear <= :experienceFrom) "
            + "AND (:ratingFrom IS NULL OR a.ratingAccordance >= :ratingFrom) "
            + "AND (:delivery IS NULL OR a.delivery = :delivery) "
            + "AND (:exchange IS NULL OR a.exchange = :exchange) " + "AND (:courses IS NULL OR a.courses = :courses)"
            + "AND (:idCountry IS NULL OR c.idCountry = :idCountry)"
            + "AND (:idAal1 IS NULL OR a1.idAdministrativeAreaLevel1 = :idAal1)"
            + "AND (:idAal2 IS NULL OR a2.idAdministrativeAreaLevel2 = :idAal2)"
            + "AND (:idAal3 IS NULL OR a3.idAdministrativeAreaLevel3 = :idAal3)" + ")")
    public List<Artist> SearchArtistWithStyles(String name, List<Long> arrayStyles, Integer gender, Integer experienceFrom, Double ratingFrom, Integer delivery,
            Integer exchange, Integer courses, Long idCountry, Long idAal1, Long idAal2, Long idAal3,
            Pageable pageable);

这是错误：

"status": 500,
"error": "Internal Server Error",
"message": "org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: {vector} [SELECT a FROM com.mushroomstudios.skink.entities.Artist a WHERE a.idArtist IN(SELECT a.idArtist FROM com.mushroomstudios.skink.entities.ArtistStyle x INNER JOIN x.style s INNER JOIN x.artist a INNER JOIN a.country c INNER JOIN a.aal1 a1 INNER JOIN a.aal2 a2 INNER JOIN a.aal3 a3 WHERE (:arrayStyles_0, :arrayStyles_1, :arrayStyles_2 IS NULL OR s.idStyle IN (:arrayStyles_0, :arrayStyles_1, :arrayStyles_2)) AND (:name IS NULL OR a.name like :name)AND (:gender IS NULL OR a.gender = :gender) AND (:experienceFrom IS NULL OR a.workStartYear <= :experienceFrom) AND (:ratingFrom IS NULL OR a.ratingAccordance >= :ratingFrom) AND (:delivery IS NULL OR a.delivery = :delivery) AND (:exchange IS NULL OR a.exchange = :exchange) AND (:courses IS NULL OR a.courses = :courses)AND (:idCountry IS NULL OR c.idCountry = :idCountry)AND (:idAal1 IS NULL OR a1.idAdministrativeAreaLevel1 = :idAal1)AND (:idAal2 IS NULL OR a2.idAdministrativeAreaLevel2 = :idAal2)AND (:idAal3 IS NULL OR a3.idAdministrativeAreaLevel3 = :idAal3)) order by a.name asc]; nested exception is java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: {vector} [SELECT a FROM com.mushroomstudios.skink.entities.Artist a WHERE a.idArtist IN(SELECT a.idArtist FROM com.mushroomstudios.skink.entities.ArtistStyle x INNER JOIN x.style s INNER JOIN x.artist a INNER JOIN a.country c INNER JOIN a.aal1 a1 INNER JOIN a.aal2 a2 INNER JOIN a.aal3 a3 WHERE (:arrayStyles_0, :arrayStyles_1, :arrayStyles_2 IS NULL OR s.idStyle IN (:arrayStyles_0, :arrayStyles_1, :arrayStyles_2)) AND (:name IS NULL OR a.name like :name)AND (:gender IS NULL OR a.gender = :gender) AND (:experienceFrom IS NULL OR a.workStartYear <= :experienceFrom) AND (:ratingFrom IS NULL OR a.ratingAccordance >= :ratingFrom) AND (:delivery IS NULL OR a.delivery = :delivery) AND (:exchange IS NULL OR a.exchange = :exchange) AND (:courses IS NULL OR a.courses = :courses)AND (:idCountry IS NULL OR c.idCountry = :idCountry)AND (:idAal1 IS NULL OR a1.idAdministrativeAreaLevel1 = :idAal1)AND (:idAal2 IS NULL OR a2.idAdministrativeAreaLevel2 = :idAal2)AND (:idAal3 IS NULL OR a3.idAdministrativeAreaLevel3 = :idAal3)) order by a.name asc]",

最后，如果我执行该查询，也可以正常工作：

@Query(value = "SELECT a FROM Artist a " + "INNER JOIN a.country c " 
            + "INNER JOIN a.aal1 a1 "
            + "INNER JOIN a.aal2 a2 " 
            + "INNER JOIN a.aal3 a3 " 
            + "WHERE (:name IS NULL OR a.name like %:name%) "
            + "AND (:gender IS NULL OR a.gender = :gender) "
            + "AND (:experienceFrom IS NULL OR a.workStartYear <= :experienceFrom) "
            + "AND (:ratingFrom IS NULL OR a.ratingAccordance >= :ratingFrom) "
            + "AND (:delivery IS NULL OR a.delivery = :delivery) "
            + "AND (:exchange IS NULL OR a.exchange = :exchange) " + "AND (:courses IS NULL OR a.courses = :courses)"
            + "AND (:idCountry IS NULL OR c.idCountry = :idCountry)"
            + "AND (:idAal1 IS NULL OR a1.idAdministrativeAreaLevel1 = :idAal1)"
            + "AND (:idAal2 IS NULL OR a2.idAdministrativeAreaLevel2 = :idAal2)"
            + "AND (:idAal3 IS NULL OR a3.idAdministrativeAreaLevel3 = :idAal3)")
    public List<Artist> SearchArtist(String name, Integer gender, Integer experienceFrom, Double ratingFrom,
            Integer delivery, Integer exchange, Integer courses, Long idCountry, Long idAal1, Long idAal2, Long idAal3,
            Pageable pageable);

第二个查询中有不好的东西吗？如果您需要更多有关实体或其他事物的信息，请提前告诉我

Answer 1

问题在这一行

 "WHERE (:arrayStyles IS NULL OR s.idStyle IN (:arrayStyles)) "

我改为了，并且工作正常

+ "WHERE s.idStyle IN (:arrayStyles) "

JPQL查询异常意外的AST节点：{vector}

1 个答案: