我有一个对象数组。我需要使用地图高阶函数转换数据。我应该使用prop函数助手进行转换。 prop函数将字符串作为参数。如何使用字符串模板文字将适当的回调传递给map:
apply plugin: 'com.android.application'
apply plugin: 'kotlin-android'
apply plugin: 'kotlin-android-extensions'
apply plugin: 'kotlin-kapt'
apply plugin: 'com.google.gms.google-services'
apply plugin: 'io.fabric'
android {
compileSdkVersion 28
defaultConfig {
applicationId "..."
minSdkVersion 21
targetSdkVersion 28
versionCode 1
versionName "..."
testInstrumentationRunner "android.support.Singleton.runner.AndroidJUnitRunner"
}
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
}
}
compileOptions {
sourceCompatibility = '1.8'
targetCompatibility = '1.8'
}
}
dependencies {
implementation fileTree(include: ['*.jar'], dir: 'libs')
implementation 'androidx.appcompat:appcompat:1.1.0'
implementation 'androidx.constraintlayout:constraintlayout:1.1.3'
implementation 'androidx.legacy:legacy-support-v4:1.0.0'
implementation 'com.google.android.material:material:1.0.0'
implementation 'androidx.recyclerview:recyclerview:1.0.0'
implementation 'androidx.cardview:cardview:1.0.0'
implementation 'com.google.firebase:firebase-core:17.2.0'
testImplementation 'junit:junit:4.12'
implementation "org.jetbrains.kotlin:kotlin-stdlib-jdk7:1.3.50"
androidTestImplementation 'androidx.test.ext:junit:1.1.1'
androidTestImplementation 'androidx.test.espresso:espresso-core:3.2.0'
// Retrofit
implementation 'com.squareup.retrofit2:retrofit:2.5.0'
implementation 'com.google.code.gson:gson:2.8.5'
implementation 'com.squareup.retrofit2:converter-gson:2.5.0'
implementation 'com.squareup.retrofit2:converter-scalars:2.3.0'
implementation 'com.squareup.okhttp3:logging-interceptor:3.10.0'
implementation 'us.belka:androidtoggleswitch:1.2.2'
implementation 'commons-io:commons-io:2.4'
implementation files('libs/mail.jar')
implementation 'com.github.droidbond:LoadingButton:0.1.5'
implementation 'com.samigehi:loadingview:1.1'
implementation 'io.github.tonnyl:whatsnew:0.1.1'
implementation 'com.github.GrenderG:Toasty:1.3.1'
implementation 'com.lsjwzh:materialloadingprogressbar:0.5.8-RELEASE'
implementation 'com.daimajia.swipelayout:library:1.2.0@aar'
implementation 'com.google.firebase:firebase-analytics:17.2.0'
implementation 'com.crashlytics.sdk.android:crashlytics:2.10.1'
testImplementation 'junit:junit:4.12'
}
答案 0 :(得分:3)
更改prop
函数以同时接受key
和obj
。现在,您可以使用Array.map()
调用它,然后将其传递给key
函数。
const data = [{"age":25,"name":"Michael"},{"age":20,"name":"David"}]
const prop = key => obj => obj[key] // or String(obj[key]) if you want the value to always be a string
const name = data.map(prop('name')).join(',')
const age = data.map(prop('age')).join(',')
console.log(name) //Michael, David
console.log(age) // 25, 20