我想通过阈值检测苹果。为此,我将图像转换为HSV,然后计算了InRange()
函数的上下限。从中获取二进制掩码。由于苹果会互相碰触,因此我使用分水岭算法将它们分开。
输入图像如下:
InRange()
操作和腐蚀后,灰色图像看起来像这样:
应用分水岭算法,输出如下所示:
问题在于,左下角的苹果被错误地检测到。只有2个苹果,显示了3个轮廓,其中一个的圆也太大了。有帮助吗?
这是我的代码,
import cv2
import numpy as np
import imutils
from scipy import ndimage
from skimage.feature import peak_local_max
from skimage.morphology import watershed
img = cv2.imread('4.jpg')
img = imutils.resize(img, width=640)
# img = cv2.pyrMeanShiftFiltering(img, 21, 51)
hsv = cv2.cvtColor(img,cv2.COLOR_BGR2HSV)
lower_1 = np.array([0,50,20])
upper_1 = np.array([80,255,255])
mask1 = cv2.inRange(hsv, lower_1, upper_1)
lower_2 = np.array([160,50,20])
upper_2 = np.array([179,255,255])
mask2 = cv2.inRange(hsv, lower_2, upper_2)
gray = mask1+mask2
kernel = np.ones((7,7),np.uint8)
gray = cv2.erode(gray,kernel,iterations = 1)
# gray = cv2.morphologyEx(gray, cv2.MORPH_OPEN, kernel)
thresh = cv2.threshold(gray, 0, 255, cv2.THRESH_BINARY | cv2.THRESH_OTSU)[1]
D = ndimage.distance_transform_edt(thresh)
localMax = peak_local_max(D, indices=False, min_distance=20,
labels=thresh)
markers = ndimage.label(localMax, structure=np.ones((3, 3)))[0]
labels = watershed(-D, markers, mask=thresh)
print("[INFO] {} unique segments found".format(len(np.unique(labels)) - 1))
for label in np.unique(labels):
if label == 0:
continue
mask = np.zeros(gray.shape, dtype="uint8")
mask[labels == label] = 255
cnts = cv2.findContours(mask.copy(), cv2.RETR_EXTERNAL,
cv2.CHAIN_APPROX_SIMPLE)
cnts = imutils.grab_contours(cnts)
c = max(cnts, key=cv2.contourArea)
((x, y), r) = cv2.minEnclosingCircle(c)
if r > 25 and r < 55:
cv2.circle(img, (int(x), int(y)), int(r), (0, 255, 0), 2)
cv2.putText(img, "{}".format(round(r)), (int(x) - 10, int(y)),
cv2.FONT_HERSHEY_SIMPLEX, 0.6, (0, 0, 255), 2)
cv2.imshow('thresh', thresh)
cv2.imshow('gray', gray)
cv2.imshow('img', img)
cv2.waitKey(0)
cv2.destroyAllWindows()