Question

首先看看我的模型：

from django.contrib.auth.models import  User
class Group(models.Model):
    person = models.ManyToManyField(
        User,
        through='PersonGroup',
        related_name='person_of_the_group'
    )


class PersonGroup(models.Model):
    group = models.ForeignKey(
        Group,
        on_delete=models.CASCADE,
        related_name='group_person_of_group'
    )
    person = models.ForeignKey(
        User, 
        on_delete=models.CASCADE
    )

这是我的观点：

class AddGroupMembers(CreateAPIView):
    serializer_class = PersonGroupSerializers
    queryset = Group.objects.all()
    lookup_field = 'pk'

    def create(self, request, *args, **kwargs):
        # Make requst data mutable
        if not request.data._mutable:
            request.data._mutable = True

        request.data['person'] = request.user.pk
        request.data['group'] = kwargs['pk']
        serializer = PersonGrouperializers(data=request.data)
        serializer.is_valid(raise_exception=True)
        self.perform_create(serializer)
        headers = self.get_success_headers(serializer.data)
        return Response(serializer.data, status=status.HTTP_201_CREATED, headers=headers)

这是我的序列号：

class PersonGroupSerializers(ModelSerializer):
    class Meta:
        model = PersonGroup
        fields = '__all__

我希望网址pk会变成pk，

http://127.0.0.1:8000/mess/api/v1/mess/<int:mess.pk>/

我希望在到达终点时，我应该能够创建PersonGroup，如果您看到我的视图，便会知道我是如何填充此表的。

我的意思是，端点网址将由Group pk中的任何一个标识，但在那里我应该能够PersonGroup

希望你明白了，有人可以告诉我如何实现吗？

Django Rest Framework CreateAPIView url主键应来自其他模型，而不是受尊重的模型

0 个答案: