Question

这是我要尝试在jobStatus对象内获取jobStatus的输出。它让我无法解析json对象

var x = 
    { "jobStatus": 
      { "jobStatus"   : "COMPLETED"
      , "jobType"     : "xyz"
      , "scheduleType": "Immediate"
      , "startTime"   : "Oct 10, 2019 2:20:45 AM"
      , "endTime"     : "Oct 10, 2019 2:20:48 AM"
      , "Time"        : "Oct 10, 2019 2:20:40 AM"
      , "phase"       : "null"
      , "submittedBy" : "random"
      } 
    }

我正在使用的代码

错误：

[$ http：baddata]数据必须是有效的JSON对象。收到：“完成”。解析错误： ”{}” https://errors.angularjs.org/1.7.8/ $ http / baddata？p0 = COMPLETED＆p1 =％7B％7D```

var y = JSON.parse(x);
var status = y.jobStatus;
var y = JSON.parse(status);
var z = y.jobStatus;
Console.log(z)

Answer 1

您无需解析任何内容的JSON或javascript对象

var x = 
    { "jobStatus": 
      { "jobStatus"   : "COMPLETED"
      , "jobType"     : "xyz"
      , "scheduleType": "Immediate"
      , "startTime"   : "Oct 10, 2019 2:20:45 AM"
      , "endTime"     : "Oct 10, 2019 2:20:48 AM"
      , "Time"        : "Oct 10, 2019 2:20:40 AM"
      , "phase"       : "null"
      , "submittedBy" : "random"
      } 
    } 

let y = x.jobStatus.scheduleType
console.log( y )
// or
let z = x['jobStatus']['jobType'] 
console.log( z )

/* ------- */
var A = 
    { jobStatus: 
      { jobStatus   : "COMPLETED"
      , jobType     : "xyz"
      , scheduleType: "Immediate"
      , startTime   : "Oct 10, 2019 2:20:45 AM"
      , endTime     : "Oct 10, 2019 2:20:48 AM"
      , Time        : "Oct 10, 2019 2:20:40 AM"
      , phase       : "null"
      , submittedBy : "random"
      } 
    } 
let B = A.jobStatus.jobType
console.log( B )
// or
let C = A['jobStatus']['scheduleType'] 
console.log( C )

无法解析JSON对象：“ [$$：baddata]数据必须是有效的JSON对象”

1 个答案: