Question

我有一个有效的json格式{"active":"false","period":"23-05-2017 to 25-05-2017","percentage":null,"value":null,"status":"inc","fixed_price":null}但是，当我尝试解码时，它会返回错误

Response内容必须是实现__toString（），＆＃34; object＆＃34;的字符串或对象。给出。

我错过了什么吗？

Answer 1

将你的json函数包装在'中。结果使用$json = '{"active":"false","period":"23-05-2017 to 25-05-2017","percentage":null,"value":null,"status":"inc","f‌ixed_price":null}'。

注意开放和关闭。然后你可以调用json_decode（$ json）

这是工匠修补匠的完整结果：

>>> $json = '{"active":"false","period":"23-05-2017 to 25-05-2017","percentage":null,"value":null,"status":"inc","fixed_price":null}'
=> "{"active":"false","period":"23-05-2017 to 25-05-2017","percentage":null,"value":null,"status":"inc","fixed_price":null}"
>>> json_decode($json);
=> {#869
 +"active": "false",
 +"period": "23-05-2017 to 25-05-2017",
 +"percentage": null,
 +"value": null,
 +"status": "inc",
 +"fixed_price": null,
   }

无法解码有效的json格式，Response内容必须是实现__toString（），＆＃34; object＆＃34;的字符串或对象。特定

1 个答案: