Question

我正在使用一个库，该库返回一个Python列表。

当我打印该列表时，它看起来像这样：

print(face_locations)

[(92, 254, 228, 118), (148, 661, 262, 547)]

print(type(face_locations))

<class 'list'>

我有一个字符串，其值："92 254 228 118;148 661 262 547"。

我想将此字符串转换为相同的数据类型。

我到目前为止所做的：

face_locations= "92 254 228 118;148 661 262 547"
face_locations= face_locations.split(";")
for i in range(len(face_locations)):
    face_locations[i] = face_locations[i].split(" ")

两个都是列表...但是当我稍后在代码中运行此函数时，出现错误：

for (top, right, bottom, left), face_encoding in zip(face_locations, face_encodings): 
    ....do something

Answer 1

使用列表推导并将str的元素映射到int。

face_locations= "92 254 228 118;148 661 262 547"
face_locations= face_locations.split(";")
[tuple(map(int, elem.split(' '))) for elem in face_locations]

输出：

[(92, 254, 228, 118), (148, 661, 262, 547)]

Answer 2

beer44有一个很好的答案，只是为了显示节省了多少工作图：

face_locations = "92 254 228 118;148 661 262 547"
face_locations = face_locations.split(";")
face_locations = [face_locations[x].split(' ') for x in range(len(face_locations))]
for sublist in face_locations:
    for i in range(len(sublist)):
        sublist[i] = int(sublist[i])
face_locations = [tuple(sublist) for sublist in face_locations]

输出：

[(92, 254, 228, 118), (148, 661, 262, 547)]

如何在Python中将字符串转换为这种类型的列表

2 个答案: