我有一个data.frames列表。我想知道如何删除该列表中名称为以下任意一项的data.frame:c("out", "Name")
。
我尝试r[names(r) != c("out", "Name")]
失败了。
r <- list(
data.frame(Name = rep("Jacob", 6),
X = c(2,2,1,1,NA, NA),
Y = c(1,1,1,2,1,NA),
Z = rep(3, 6),
out = rep(1, 6)),
data.frame(Name = rep("Jon", 6),
X = c(1,NA,3,1,NA,NA),
Y = c(1,1,1,2,NA,NA),
Z = rep(2, 6),
out = rep(1, 6)),
data.frame(Name = rep("Jon", 6),
X = c(1,NA,3,1,NA,NA),
Y = c(1,1,1,2,2,NA),
Z = rep(2, 6),
out = rep(2, 6)),
data.frame(Name = rep("Jim", 6),
X = c(1,NA,3,1,NA,NA),
Y = c(1,1,1,2,2,NA),
Z = rep(2, 6),
out = rep(1, 6)))
答案 0 :(得分:2)
我们可以使用%in%
r[!names(r) %in% c("out", "Name")]
使用更新的数据
lapply(r, function(x) x[setdiff(names(x), c("out", "Name"))])
答案 1 :(得分:0)
尝试一下:
r [names(r)!='out'] [names(r [names(r)!='out'])!='Name']