Here is a sample of what output should look like!!
我显示购买笔记本电脑订单摘要的程序使用(1)while循环处理多台笔记本电脑,使用(2)if-else获取笔记本电脑的名称/价格;或错误消息“无效选择!请重试。”,(3)嵌套是否指出笔记本电脑的选择何时有效才能继续进行其余处理。还有(4)个嵌套选项,用于仅在购买笔记本电脑时打印订单摘要。
当我输入一个无效数字(例如8)作为选择时,if语句仍将执行,而不是其下的else。
当我输入有效数字作为选择时,它会询问数量,但是当我输入数量时,我如何将用户输入添加到订单摘要中,而不是使程序返回循环顶部?
我是Java的新手,我的代码应该如何产生正确的输出?
这是我当前拥有的代码(JAVA)
public static void main(String[] args) {
char cont='Y';
int qty=0;
int trigger=0;
double total=0;
double subtotal=0;
double tax=0;
double price;
double lineItem=0;
String orderSummary=" ";
String laptop=" ";
Scanner input = new Scanner(System.in);
Calendar dateTime = Calendar.getInstance();
//Displays a list of laptops with prices and asked user for their choice. Prompt #1
int choice = 0;
while (choice >= 0) {
System.out.printf("%nTOP LAPTOPS OF %tY"
+ "%n%n1. %-23s %7s $%,9.2f"
+ "%n2. %-23s %8s %,9.2f"
+ "%n3. %-23s %8s %,9.2f"
+ "%n4. %-23s %8s %,9.2f"
+ "%n5. %-23s %8s %,9.2f"
+ "%n%nEnter your choice: ",
dateTime,
"HP Envy 13", " ", 799.99,
"Asus ZenBook 13 UX333FA", " ", 849.99,
"Dell XPS 13", " ", 989.99,
"Alienware Area 51-m", " ", 1999.99,
"Razer Blade Stealth", " ", 1299.00);
choice = input.nextInt();
if (choice < 6 || choice > 0) {
System.out.printf("Enter the quantity:");
qty = input.nextInt();
} else {
System.out.printf("Invalid choice! Try again.%n%n");
System.out.printf("Enter 'Y' to add a laptop to your purchase or 'N' to exit: ");
cont = input.next().charAt(0);
}
if (cont == 'Y') {
continue;
}
if (cont == 'N') {
System.exit(0);
}
//The following if-else prints a $ sign for the first line item
if (trigger == 1) {
orderSummary += String.format("%n%, -9d %-30s %8s $%,17.2f", qty, laptop, " ", lineItem);
trigger = 0;
} //End else for no $ sign
//The following statement prints the order summary of the laptops purchased.
//This should be done when there are no more laptops to process
if (choice > 0) {
if (choice < 6) {
tax = subtotal * .0825;
total = subtotal + tax;
orderSummary += String.format("%n%n%34s Subtotal %6s %,17.2f"
+ "%n%31s Tax @ 8.25%% %6s %,17.2f"
+ "%n%n%37s TOTAL %5s $%,17.2f%n",
" ", " ", subtotal,
" ", " ", tax,
" ", " ", total);
System.out.printf("%s", orderSummary);
break;
} //End if valid choice range ends print order summary
} //End if valid choice range begins
}
}
答案 0 :(得分:0)
因为语句规则AND(&&&)或(&&)对应于布尔代数。
如果(选择<6 ||选择> 0) 对应于'如果选择<8'为True或'选择> 0'为真则整个表达式为真
例如,对于选定的8个,它将为TRUE,因此不会发生
尝试if(选择> 0 &&选择<6)
然后考虑“业务逻辑”,准备存储和重用,组织变量进行计算,请参见以下示例
import java.util.*;
public class Example{
public static void main(String[] args) {
String [] product = {"HP Envy 13","Asus ZenBook 13 UX333FA","Dell XPS 13","Alienware Area 51-m","Razer Blade Stealth"};
double [] unit_rate = {799.99, 849.99, 989.99, 1999.99, 1299.00};
int [] user_selectected_qty = new int [product.length];
double total = 0;
boolean again = true;
Scanner input = new Scanner(System.in);
int choice,qty;
while (again)
{
System.out.println("TOP LAPTOPS");
for(int i=1; i<product.length ; i++)
System.out.println(""+i+".\t"+product[i]+"\t\t\t"+unit_rate[i]);
System.out.println("Enter your choice:");
choice = input.nextInt();
// SELECTION PROCESS
if (choice >0 && choice <6)
{
System.out.println("Enter the quantity for "+product[choice]+":");
qty = input.nextInt();
user_selectected_qty[choice]+=qty;
// ... ASK TO DO IT AGAIN...
again=false;
}
else
{
System.out.println("Wrong choice:");
}
}
// BEFORE END SHOW SUMMARY ...COMPUTE TOTAL ...
System.out.println("LAPTOP ORDER SUMARY");
for(int i=1; i<product.length ; i++)
if (user_selectected_qty[i] > 0)
System.out.println(""+user_selectected_qty[i]+"\t"+product[i]+"\t\t\t"+unit_rate[i]*user_selectected_qty[i]);
}
}