Question

此函数要求loLimit和hiLimit之间的整数，并允许用户安全地输入它。它一直询问，直到用户输入合法范围内的数字。然后它返回合法号码。

NULL

但是，我的输出行为奇怪，好像loLimit值来回变化。此外，数字仅在输入两次后记录。

The correct output should be:
Please enter an integer between 32 and 127: 19
Please enter an integer between 32 and 127: 128
Please enter an integer between 32 and 127: 48
Please enter an integer between 48 and 127: 47
Please enter an integer between 48 and 127: 65

这是我的代码：

Please enter an integer between 32 and 127: 2
Please enter an integer between 32 and 127: 150
Please enter an integer between 32 and 127: 56
Please enter an integer between 32 and 127: 56
Please enter an integer between 56 and 127: 66
Please enter an integer between 32 and 127: 66
Please enter an integer between 66 and 127: 77

Answer 1

您调用enterNumber（）函数5次，因此会接受5个接受的值：

  enterNumber(32,127);
  Please enter an integer between 32 and 127: 56 
  1st accepted number

  int min=enterNumber(32,127);
  Please enter an integer between 32 and 127: 56  // 2nd one
  2nd accepted number

  enterNumber(min,127);
  Please enter an integer between 56 and 127: 66
  3rd accepted answer.

  int max=enterNumber(enterNumber(32,127),127);    //called twice
  Please enter an integer between 32 and 127: 66
  Please enter an integer between 66 and 127: 77
  4th and 5 th accepted answer

您可以通过删除第一个和第三个enternumber调用来更正您的逻辑。

   int enterNumber (int loLimit, int hiLimit){
   int min;
   int max;

   do {
      printf("Please enter an integer between %d and %d:\n", loLimit, hiLimit);
      scanf("%d", &min);
      }
   while (min<loLimit || min>hiLimit);
   return min;
  }

  int main(){
 // enterNumber(32,127); comment out this
  int min=enterNumber(32,127);

  // enterNumber(min,127);
   int max=enterNumber(min,127);
   int no=enterNumber(min,max);

}

首先它接受最小值，然后是最大值，最后在此范围之间输入一个。

while循环输出不正确

1 个答案: