Question

我目前正在尝试构建一个读取文件的程序，扫描该文件，并输出该文件中被“标记”包围的所有单词。我目前很难过，希望得到一些帮助！

#include <iostream>
// For file I/O:
#include <fstream>
#include <cstdlib>
#include <iomanip>

using namespace std;

// Prototype the count function so we can have it below it's first
// use in main().
void count(istream& in, int& lines, int& words, int& characters);
/*
 * wc <filename>
  */

int main(int argc, char *argv[])
{
 if (argc < 2) {
   cerr << "Usage: wc <filename>" << endl;
  return 0;
 }
 // Open the file specified by argv[1] for reading:
  // Constructs a ifstream object called "in":
  ifstream in(argv[1]);
  // Was there a problem opening the file?
  if (!in.good()) {
   cerr << "Unable to open file [" << argv[1] << "] for reading." << endl;
   return 1;
  }

   int lines = 0, words = 0, characters = 0;
  count(in, lines, words, characters);
   cout << setw(5) << lines << " " << words << " " <<
    characters << " " <<           argv[1] << endl; 

  // Close the input stream:
  in.close();
   }

   void count(istream& in, int& lines, int& words, int& characters) 
   {
   int i;
   char s;
   int ch;
   bool inword = false;

  // Read until the end of file is reached, or there was an error:
  while (!in.eof()) {
   // Read a character from the input stream "in":
    s = in.get(); //Set char s = in.get
     for(i=0; s != 0; i++){ //Loop to iterate through the characters
      while(s == '"'){ //While s is equal "
       cout << s << endl; // Print s
        if(s == '"') // If we hit another ", then we break
        break;
      }
    }
    if (in.good() == false) return;
   characters++;
   if (!isspace(ch) && !inword) {
    inword = true;
    words++;
    } else if (isspace(ch) && inword) {
     inword = false;
    }
    if (ch == '\n') lines++;
    }
    }

Answer 1

你的算法似乎错了..在for循环中你比较了＆＃39; s＆＃39;但是你没有更新它...在你的主循环（QnD）中试试这样的东西：

while (!in.eof() && (s = in.get()) != '"'); // read to first quote char
/* this is the word we want.. run to end quote marks.. */
while (!in.eof() && (s = in.get()) != '"') {
    cout << s;
}
cout << endl;

无限循环和获取不正确的输出

1 个答案: