Question

我正在尝试使用redux切换（显示/隐藏）react组件，但出现错误：

Error: An error occurred while selecting the store state.

当我通过直接调用访问状态时，此错误消失。

更改此内容：

const show = useSelector(state => state.toggle[id]);

对此：

const show = useSelector(state => state.empty);

切换组件

import React from 'react';
import {useSelector} from 'react-redux';


export const Toggle = ({id, children}) => {
  const show = useSelector(state => state.toggles[id]);
  return show ? children : null;
};

减速器

const initialState = {
  empty: false
};

export default (state = initialState, action) => {
  switch (action.type) {
    case 'SHOW':
      return {...state, [action.payload]: true};
    case 'HIDE':
      return {...state, [action.payload]: false};
    default:
      return state;
  }
};

动作

export const showToggle = id => ({type: 'SHOW', payload: id});
export const hideToggle = id => ({type: 'HIDE', payload: id});

子组件

import React from 'react';

export const MyComponent = ({onClick}) => {
  return (
    <div>
      Do something awesome here
      <button onClick={onClick}>Ok</button>
    </div>
  )
};

主要组件

import React from 'react';
import {useDispatch} from 'react-redux';
import {Toggle} from './Toggle';
import {MyComponent} from './MyComponent';
import {showToggle, hideToggle} from './actions';

export const SomeOtherComponent = () => {
  const dispatch = useDispatch();
  const toggleId = 'empty';
  return (
    <div>
            <span>Say something<span>
            <Toggle id={toggleId}>
              <MyComponent onClick={() => dispatch(hideToggle(toggleId))}/>
            </Toggle>
            <button onClick={() => dispatch(showToggle(toggleId))}>Show my component</button>
    </div>
)};

基本上，我想按ID切换组件，因为我想添加更多可以切换的组件。

Answer 1

您的reducer不是数组，因此会损坏。

如果您将减速器更改为此有效吗？

const initialState = [];

export default (state = initialState, action) => {
  switch (action.type) {
    case 'SHOW':
      return {...state, [action.payload]: true};
    case 'HIDE':
      return {...state, [action.payload]: false};
    default:
      return state;
  }
};

和您的Toggle组件：

import React from 'react';
import {useSelector} from 'react-redux';


export const Toggle = ({id, children}) => {
  const show = useSelector(state => state[id]);
  return show ? children : null;
};

替代：

const initialState = {
  show_list: [],
  // other state keys
};

export default (state = initialState, action) => {
  switch (action.type) {
    case 'SHOW':
      let show_list = state.show_list;
      show_list[action.payload] = true;
      return {...state, show_list};
    case 'HIDE':
      let show_list = state.show_list;
      show_list[action.payload] = false;
      return {...state, show_list};
    default:
      return state;
  }
};

切换组件：

import React from 'react';
import {useSelector} from 'react-redux';


export const Toggle = ({id, children}) => {
  const show = useSelector(state => state.show_list[id]);
  return show ? children : null;
};

Answer 2

您的状态没有名为toggles的任何属性，而是直接将切换状态保留在state对象中作为键/值。

所以改变

const show = useSelector(state => state.toggles[id]);

到

const show = useSelector(state => state[id]);

如何使用钩子在Redux中切换React组件？

切换组件

减速器

动作

子组件

主要组件

2 个答案: