如何解决-Bootcamp-cordapp中的NotSerializableException。测试合同时

时间:2019-09-20 18:07:26

标签: java corda bootcamp

我正在尝试为Contract运行corda-bootcamp测试用例。我按照视频中的说明进行操作,但是在尝试进行合同测试时遇到错误

java.io.NotSerializableException: data(net.corda.core.contracts.ContractState) -> Trying to build an object serializer for bootcamp.TokenState, but it is not constructible from its public properties, and so requires a custom serialiser.

有人可以帮忙,如何解决呢?我发现了一个类似的问题-here,但这没有用。

以下是使用的令牌状态

package bootcamp;

import com.google.common.collect.ImmutableList;
import net.corda.core.contracts.BelongsToContract;
import net.corda.core.contracts.ContractState;
import net.corda.core.identity.AbstractParty;
import net.corda.core.identity.Party;

import java.util.ArrayList;
import java.util.List;

/* Our state, defining a shared fact on the ledger.
 * See src/main/java/examples/ArtState.java for an example. */
@BelongsToContract(TokenContract.class)
public class TokenState implements ContractState {

    private Party issuer;
    private Party owner;
    private int amount;

    public TokenState(Party issuer, Party owner, int amount) {
        this.issuer = issuer;
        this.owner = owner;
        this.amount = amount;
    }

    public Party getIssuer() {
        return issuer;
    }

    public Party getOwner() {
        return owner;
    }

    public int getAmount() {
        return amount;
    }

    public List<AbstractParty> getParticipants() {
        List<AbstractParty> participants = new ArrayList<>();
        participants.add(issuer);
        participants.add(owner);
        return participants;
    }
}

抛出错误的测试用例,

private final TestIdentity alice = new TestIdentity(new CordaX500Name("Alice", "", "GB"));
    private final TestIdentity bob = new TestIdentity(new CordaX500Name("Bob", "", "GB"));
    private MockServices ledgerServices = new MockServices(new TestIdentity(new CordaX500Name("TestId", "", "GB")));

    private TokenState tokenState = new TokenState(alice.getParty(), bob.getParty(), 1);

@Test
public void tokenContractRequiresZeroInputsInTheTransaction() {
        transaction(ledgerServices, tx -> {
            // Has an input, will fail.
            tx.input(TokenContract.ID, tokenState);
            tx.output(TokenContract.ID, tokenState);
            tx.command(Arrays.asList(alice.getPublicKey(), bob.getPublicKey()), new TokenContract.Commands.Issue());
            tx.fails();
            return null;
        });

        transaction(ledgerServices, tx -> {
            // Has no input, will verify.
            tx.output(TokenContract.ID, tokenState);
            tx.command(Arrays.asList(alice.getPublicKey(), bob.getPublicKey()), new TokenContract.Commands.Issue());
            tx.verifies();
            return null;
        });
    }

1 个答案:

答案 0 :(得分:0)

Corda使用其自己的序列化框架,该框架要求Java编译器在生成字节码时保留参数名称,以便以后可以正确地重新创建对象。

要与IntelliJ一起使用,请执行以下操作:

  1. 打开设置:

    • Windows:文件->设置
    • osX / Ubuntu:IntelliJ IDEA->首选项
  2. 转到构建,执行,部署->编译器-> Java编译器 在“其他命令行参数”字段中写入-parameters

enter image description here

  1. 完全重建项目(构建->重建项目)

enter image description here