“如何将列表中的字符串计为-lst =（'abcdefgabc'）”。输出应为a = 2，b = 2，c = 2，d = 1，e = 1，f = 1，g = 1

Question

尝试计算lst=('abcdefgabc')

处的字符串计数

lst=('abcdefgabc')
for i in lst:
    lst.count(i)
    print(i,(lst.count(i)))

输出应为a=2, b=2, c=2, d=1,e=1,f=1,g=1

Answer 1

这是您要找的东西吗？

lst=('abcdefgabc')
new_list = []
for i in lst:
    a = i+"="+str((lst.count(i)))
    new_list.append(a)
b = sorted(set(new_list))
print(b)
for x in b:
    print(x)

输出：

['a=2', 'b=2', 'd=1', 'c=2', 'f=1', 'e=1', 'g=1']
a=2
b=2
d=1
c=2
f=1
e=1
g=1