我是初学者。
我从SQLite获得String。
WKT = cursor.getString(cursor.getColumnIndex(polygon));
WKT = WKT.replaceAll(",", ", ");
它看起来像String =(1.00 2.00,3.00 4.00,5.00 6.00,.....)。 如何将其切换为String(2.00 1.00,4.00 3.00,6.00 5.00,......)。
感谢。
答案 0 :(得分:1)
试试这个
private static void testMethod() {
String result = "(A B, C D, E F)";
String resultTmp = result;
resultTmp = resultTmp.replace("(", "");
resultTmp = resultTmp.replace(")", "");
String[] aryResult = resultTmp.split(",");
String[] finalResult = reverseString(aryResult);
StringBuilder strBuilder = new StringBuilder();
for (int i = 0; i < finalResult.length; i++) {
String dfgf = strBuilder.toString().equals("") ? "" : ",";
strBuilder.append(dfgf);
strBuilder.append(finalResult[i]);
}
String newString = strBuilder.toString();
System.out.println("RESULT : " + newString);
}
public static String[] reverseString(String[] words)
{
String[] t = new String[words.length];
for (int i = 0; i < words.length; i++)
{
t[i] = "";
for (int j = words[i].length() - 1; j >= 0; j--)
t[i] += words[i].charAt(j);
}
return t;
}
答案 1 :(得分:1)
Follow below steps
1)Split string with ","
2)User Reverse() function to reverse the string(AB->BA)
3)Store the result in to an array.
Repeat the step until you split the last entry from sql lite.
答案 2 :(得分:0)
尝试这个逻辑,它在c和c ++中工作。
int Groups = 1; // Count 1 for the first group of letters
for ( int Loop1 = 0; Loop1 < strlen(String); Loop1++)
if (String[Loop1] == ' ') // Any extra groups are delimited by space
Groups += 1;
int* GroupPositions = new int[Groups]; // Stores the positions
for ( int Loop2 = 0, Position = 0; Loop2 < strlen(String); Loop2++)
{
if (String[Loop2] != ' ' && (String[Loop2-1] == ' ' || Loop2-1 < 0))
{
GroupPositions[Position] = Loop2; // Store position of the first letter
Position += 1; // Increment the next position of interest
}
}
答案 3 :(得分:0)
试试这个..
private static void testTwo() {
String result = "(1.00 2.00, 3.00 4.00, 5.00 6.00)";
String resultTmp = result;
resultTmp = resultTmp.replace("(", "");
resultTmp = resultTmp.replace(")", "");
String[] aryResult = resultTmp.split(",");
for (int i = 0; i < aryResult.length; i++) {
String str = aryResult[i].trim();
String[] sdf = str.split(" ");
aryResult[i] = reverseArray(sdf);
}
String strResult = Arrays.toString(aryResult).replace("[", "(").replace("]", ")");
System.out.println("RESULT : " + strResult);
}
public static String reverseArray(String[] words)
{
for(int i = 0; i < words.length / 2; i++)
{
String temp = words[i];
words[i] = words[words.length - i - 1];
words[words.length - i - 1] = temp;
}
return ((Arrays.toString(words)).replace("[", "")).replace("]", "").replace(",", "");
}
答案 4 :(得分:0)
<强>#。如果您想交换sampleIndex[i-1]
,请使用以下方法:
sub-string
使用:强>
public String swapString(String str) {
str = str.replace("(", "");
str = str.replace(")", "");
String[] array = str.split(", ");
StringBuilder result = new StringBuilder();
result.append("(");
for (int i = 0; i < array.length; i++) {
String[] temp = String.valueOf(array[i]).split(" ");
result.append(temp[1]);
result.append(" ");
result.append(temp[0]);
if (i != array.length -1)
result.append(", ");
}
result.append(")");
return result.toString();
}
<强>输出:强>
String yourString = "(1.00 2.00, 3.00 4.00, 5.00 6.00)";
Log.d("ARRAY", "Before Swap: " + yourString);
yourString = swapString(yourString);
Log.d("ARRAY", "After Swap: " + yourString);
<强>#。如果您想交换D/ARRAY: Before Swap: (1.00 2.00, 3.00 4.00, 5.00 6.00)
D/ARRAY: After Swap: (2.00 1.00, 4.00 3.00, 6.00 5.00)
,请使用以下方法:
char
使用:强>
public String swapChar(String str) {
// Convert string to char array
char[] array = str.toCharArray();
for (int i = 1; i < array.length - 1; i+=5) {
// Swap char
char temp = array[i];
array[i] = array[i+2];
array[i+2] = temp;
}
return String.valueOf(array);
}
<强>输出:强>
String yourString = "(A B, C D, E F, G H, I J)";
Log.d("ARRAY", "Before Swap: " + yourString);
yourString = swapChar(yourString);
Log.d("ARRAY", "After Swap: " + yourString);
希望这会有所帮助〜