Question

通过查找主要记录然后在线程中循环来对相关事务求和，我的搜索速度非常慢。我试图让它在一个单一的声明中工作，已经接近但仍然有记录，交替借记和信用。

我无法弄清楚如何将借记和贷记行拉到列中，因此每个日期和作业 y会有一行结果。

SELECT j.dtmInvoicedOn, j.strJobKey, c.strCustName, strTransType, 
     SUM(r.dblTransactionAmount) AS SUM_dblTotalCharge 
     FROM tbljobs AS j
     INNER JOIN tblreceivledger AS r ON j.strJobKey = r.strJobKey 
     INNER JOIN tblcustomers AS c ON j.intCustomerID = c.intCustomerID 
     WHERE c.strCustomerName = 'Acme Runners Inc'
     GROUP BY j.strJobKey, c.strCustName, strTransType
     ORDER BY dtmInvoicedOn, strJobKey;

产生这样的输出，几乎是交替的借方和贷方总和

+----------------+---------------+------------------+--------------------+--------------------+
| dtmInvoicedOn  | strJobKey     | strCustomerName  | strTransactionType | SUM_dblTotalCharge |
+----------------+---------------+------------------+--------------------+--------------------+
| 2008-07-03     | 270876-1      | Acme Runners Inc | credit             |           -5531.52 | 
| 2008-07-11     | 270880-1      | Acme Runners Inc | debit              |            5058.54 | 
| 2008-07-11     | 270880-1      | Acme Runners Inc | credit             |           -5058.54 | 
| 2008-07-18     | 271468-1      | Acme Runners Inc | debit              |            5290.17 | 
| 2008-07-18     | 271468-1      | Acme Runners Inc | credit             |           -5290.17 | 
| 2008-11-07     | 286049-1      | Acme Runners Inc | debit              |            5230.44 | 
| 2008-11-14     | 286051-1      | Acme Runners Inc | debit              |            5375.14 | 
| 2008-11-21     | 286107-1      | Acme Runners Inc | debit              |            5572.33 | 
| 2008-11-28     | 286112-1      | Acme Runners Inc | debit              |            5123.42 |

所以我希望它看起来像：

+----------------+---------------+------------------+----------+----------+
| dtmInvoicedOn  | strJobKey     | strCustomerName  |   credit |    debit |
+----------------+---------------+------------------+----------+----------+
| 2008-07-03     | 270876-1      | Acme Runners Inc | -5531.52 |        0 |
| 2008-07-11     | 270880-1      | Acme Runners Inc | -5058.54 |  5058.54 | 
| 2008-07-18     | 271468-1      | Acme Runners Inc | -5290.17 |  5290.17 | 
| 2008-11-07     | 286049-1      | Acme Runners Inc |        0 |  5230.44 | 
| 2008-11-14     | 286051-1      | Acme Runners Inc |        0 |  5375.14 | 
| 2008-11-21     | 286107-1      | Acme Runners Inc |        0 |  5572.33 | 
| 2008-11-28     | 286112-1      | Acme Runners Inc          0 |  5123.42 |

请注意，服务器当前正在运行mysql，但稍后将迁移到postgres和sqlite。

感谢

Answer 1

这应该做的工作：

SELECT j.dtmInvoicedOn, j.strJobKey, c.strCustName, strTransType, 
     SUM(CASE WHEN strTransType='credit' THEN r.dblTransactionAmount ELSE 0 END) AS SUM_CREDIT,
     SUM(CASE WHEN strTransType='debit' THEN r.dblTransactionAmount ELSE 0 END) AS SUM_DEBIT
FROM tbljobs AS j
     INNER JOIN tblreceivledger AS r ON j.strJobKey = r.strJobKey 
     INNER JOIN tblcustomers AS c ON j.intCustomerID = c.intCustomerID 
WHERE c.strCustomerName = 'Acme Runners Inc'
GROUP BY j.strJobKey, c.strCustName
ORDER BY dtmInvoicedOn, strJobKey;

Answer 2

您希望摆脱交易类型，并且有两个字段总计取决于借记或贷记。

SELECT j.dtmInvoicedOn
, j.strJobKey
, c.strCustName
, Sum(Case When strTransactionType = 'credit' then r.dblTransactionAmount else 0 end) as credit
, Sum(Case When strTransactionType = 'debit' then r.dblTransactionAmount else 0 end) as debit   
FROM tbljobs AS j     
INNER JOIN tblreceivledger AS r ON j.strJobKey = r.strJobKey      
INNER JOIN tblcustomers AS c ON j.intCustomerID = c.intCustomerID      
WHERE c.strCustomerName = 'Acme Runners Inc'     
GROUP BY j.dtmInvoicedOn
, j.strJobKey
, c.strCustName
ORDER BY dtmInvoicedOn, strJobKey;

行中的SQL总和被拉入列中？

2 个答案: