这是我的查询
select * from dbo.tblHRIS_ChildDetails where intSID=463
输出:
intCHID intsid nvrchildname nvrgender dttchildDOB Occupation
3 463 SK Female 2001-12-11 00:00:00.000 Studying
4 463 SM Male 2007-10-08 00:00:00.000 Student
我需要像这样的输出这是查询是动态的,它可能会根据intSID返回n行
chidname1 gender DOB childoccupation1 chidname2 gender DOB childoccupation2
SK female 2001-12-11 00:00:00.000 studying SM Male 2007-10-08 00:00:00.000 Student
答案 0 :(得分:2)
对于此类数据,您需要同时实现SQL Server的UNPIVOT
和PIVOT
功能。 UNPIVOT
从多列中获取数据并将其放入两列,然后应用PIVOT
将数据转换回列。
如果您知道要转换的所有值,那么您可以对其进行硬编码,类似于:
select *
from
(
select value, col+'_'+cast(rn as varchar(10)) col
from
(
select nvrchildname,
nvrgender,
convert(varchar(10), dttchildDOB, 120) dttchildDOB,
occupation,
row_number() over(partition by intsid order by intCHID) rn
from tblHRIS_ChildDetails
where intsid = 463
) src
unpivot
(
value
for col in (nvrchildname, nvrgender, dttchildDOB, occupation)
) unpiv
) src1
pivot
(
max(value)
for col in ([nvrchildname_1], [nvrgender_1],
[dttchildDOB_1], [occupation_1],
[nvrchildname_2], [nvrgender_2],
[dttchildDOB_2], [occupation_2])
) piv
现在,如果要转换的值有未知数量,那么可以使用动态SQL:
DECLARE @colsUnpivot AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX),
@colsPivot as NVARCHAR(MAX)
select @colsUnpivot = stuff((select ','+quotename(C.name)
from sys.columns as C
where C.object_id = object_id('tblHRIS_ChildDetails') and
C.name not in ('intCHID', 'intsid')
for xml path('')), 1, 1, '')
select @colsPivot = STUFF((SELECT ','
+ quotename(c.name
+'_'+ cast(t.rn as varchar(10)))
from
(
select row_number() over(partition by intsid order by intCHID) rn
from tblHRIS_ChildDetails
) t
cross apply sys.columns as C
where C.object_id = object_id('tblHRIS_ChildDetails') and
C.name not in ('intCHID', 'intsid')
group by c.name, t.rn
order by t.rn
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query
= 'select *
from
(
select col+''_''+cast(rn as varchar(10)) col, value
from
(
select nvrchildname,
nvrgender,
convert(varchar(10), dttchildDOB, 120) dttchildDOB,
occupation,
row_number() over(partition by intsid order by intCHID) rn
from tblHRIS_ChildDetails
where intsid = 463
) x
unpivot
(
value
for col in ('+ @colsunpivot +')
) u
) x1
pivot
(
max(value)
for col in ('+ @colspivot +')
) p'
exec(@query)
两个查询的结果是:
| NVRCHILDNAME_1 | NVRGENDER_1 | DTTCHILDDOB_1 | OCCUPATION_1 | NVRCHILDNAME_2 | NVRGENDER_2 | DTTCHILDDOB_2 | OCCUPATION_2 |
-----------------------------------------------------------------------------------------------------------------------------
| SK | Female | 2001-12-11 | Studying | SM | Male | 2007-10-08 | Student |
答案 1 :(得分:0)
您必须提供不同的列名称,但除此之外,它很简单。但正如其他人所说的那样,这种情况并不常见,如果你想打印一些包含两列的报告,那就好了。
select
max(case when intCHID=1 then nvrchildname end) as chidname1,
max(case when intCHID=1 then gender end) as gender1,
max(case when intCHID=1 then dttchildDOB end) as DOB1,
max(case when intCHID=1 then Occupation end) as cildOccupation1,
max(case when intCHID=2 then nvrchildname end) as chidname2,
max(case when intCHID=2 then gender end) as gender2,
max(case when intCHID=2 then dttchildDOB end) as DOB2,
max(case when intCHID=2 then Occupation end) as cildOccupation2
from
dbo.tblHRIS_ChildDetails
where
intSID=463