Question

所以我有一个值为["folderid":"DTSZ", "folderid":"IEACF6FVGG", "folderid":"IEACKQC6A"]的array1和另一个值为["title":"firsttitle", "title":"second","title":"thirdtitle"]的数组2

现在可以说使用javascript，我想将其另存为json对象。

 [

      {"folderid":"DTSZ","title":"firsttitle"},                
      {"folderid":"IEACF6FVGG", "title":"second"},
      {"folderid":"IEACKQC6A", "title":"thirdtitle"}
 ]

我尝试循环播放和连续播放，但无法正常工作。

array1= ["folderid":"DTSZ", "folderid":"IEACF6FVGG", "folderid":"IEACKQC6A"] ;

array2 = ["title":"firsttitle", "title":"second","title":"thirdtitle"];

使用json对象获取数组

[
      {"folderid":"DTSZ","title":"firsttitle"},                
      {"folderid":"IEACF6FVGG", "title":"second"},
      {"folderid":"IEACKQC6A", "title":"thirdtitle"}
 ]

Answer 1

在JavaScript中，数组仅包含值，在您的示例中，该数组无效，因为您尝试添加直接的key: values元素。即

["folderid":"DTSZ"] // invalid !! (notice semicolon)

["folderid", "DTSZ"] // VALID (notice comma)

如果要转换为有效数组然后转换为对象，则可以使用诸如条目之类的东西，它们是数组的数组。

让我们以第一个示例为例，将其转换为条目：

const arr1 = [["folderid", "DTSZ"], ["folderid", "IEACF6FVGG"], ["folderid","IEACKQC6A"]]

然后将其转换为对象，您可以像这样使用Object.fromEntries：

const obj1 = Object.fromEntries(entries);

因此，首先要集中精力将您最初的无效数组转换为条目，然后完成工作！

Answer 2

使用以下代码。

var a = [{ "folderid": "DTSZ" }, { "folderid": "IEACF6FVGG" }, { "folderid": "IEACKQC6A" }]
var b = [{ "title": "firsttitle" }, { "title": "second" }, { "title": "thirdtitle" }]


var newObject = a.map((o, index) => {
    const temp = Object.assign(o, b[index]);
   return temp;
});

console.log('output ----  ', newObject)

我如何加入两个数组并创建对象的json数组

2 个答案: