Question

我正在尝试制作一个程序，其中该程序向用户询问数字，并一直询问直到输入空白行。然后，它应该打印出有多少个偶数。现在唯一的问题是，每输入一个空行都会给我这个错误：ValueError: invalid literal for int() with base 10: ''。你能给出解决方案吗？

number = int(input('Enter your number: '))
count = 0
even = []

while number:

    even.append(number)
    if number %2 == 0:
        number = int(input('Enter your number: '))  
    else:
        number = int(input('Enter your number: '))

number = int(input('Enter your number: '))
for nums in evens:
   count+=1
   print(f'Your even numbers are: {nums} ')

Answer 1

检查用户提供的号码。将任何字符串强制转换为int可能导致ValueError

number = input('Enter your number')
if number.isdigit():
    number = int(number)
else:
    print('Please provide a correct number value')

Answer 2

尝试以下代码：

number = input("Enter Number:\t")
my_list = []
while True:
    if number.isdigit():
        my_list.append(int(number))
        number = input("Enter Number:\t")
        continue
    elif number.isspace():
        print()
        print("The Even Numbers are:\t")
        print(*[var for var in my_list if var%2==0])
        break
    else:
        print("Wrong input Enter number or press space. Start from beginning")
        break

Answer 3

isExit=False
str_number=input('Enter your number: ')
if str_number.isnumeric():
    number = int(str_number)
else:
    isExit=True
count = 0
even = []

while not isExit:
    if number %2 == 0:
        even.append(number)
    str_number=input('Enter your number: ')
    if str_number.isnumeric():
        number = int(str_number)
    else:
        isExit=True
if even:
    for nums in even:
        count+=1
        print(f'Your even numbers are: {nums} ')
else:
    print('No even numbers')

希望这会根据您的需要

Jupyter Notebook-ValueError：以10为底的int（）的无效文字：''

3 个答案: