如何在Swift中将Objc-C NSUInteger [] = {0,1,2}表示为UnsafeMutablePointer <UInt>？

Question

Objc-C标头定义：

- (int)printPDFAtPath:(NSString *)pdfPath pages:(NSUInteger [])indexes length:(NSUInteger)length copy:(int)nCopy;

使用此功能的objc-C代码示例：

NSUInteger pageIndexes[] = {0}; printResult = [self.ptp printPDFAtPath:selectedPDFFilePath pages:pageIndexes length:length copy:self.numberOfPaper];

雨燕期望：

func printPDF(atPath pdfPath: String!, pages indexes: UnsafeMutablePointer<UInt>!, length: UInt, copy nCopy: Int32) -> Int32

如何在Swift中将NSUInteger pageIndexes[] = {0};表示为UnsafeMutablePointer<UInt>？

Answer 1

您可以简单地通过[UInt]将Swift &数组作为进出参数传递，这会将数组元素存储的地址传递给（Objective-）C函数：

var pageIndexes: [UInt] = [1, 2, 3]
ptp.printPDF(atPath: "path", pages: &pageIndexes, length: UInt(pageIndexes.count), copy: 1)

有关更多信息，请参见

• Using Imported C Functions in Swift，
• Interacting with C Pointers。