Question

我有一个数组名称JSON，以及如何检查每个部门的薪水并找到薪水最高的部门

var json = [
   {
       id: 1,
       name: 'BInit',
       salary: 20000,
       department_slug: "it",
       department: 'IT'
   },
   {
       id: 2,
       name: 'BaaaInit',
       salary: 25000,
       department_slug: "hr",
       department: 'HR'
   },
   {
       id: 3,
       name: 'At',
       salary: 15000,
       department_slug: "finance",
       department: 'FInance'
   },
   {
       id: 4,
       name: 'aas',
       salary: 35000,
       department_slug: "finance",
       department: 'FInance'
   }
];

我会尝试

for(var i=0; i<json.length; i++){
   for (var j= i; j<json.length; j++){

   }
}

我需要这个数组中最高薪的部门

Answer 1

编辑：我意识到我并没有完全理解原来的问题：找到薪水最高的部门

我更改了代码以查找薪水最高的部门（因为可能有多个部门拥有相同的薪水总额

请注意，我认为属性 department_slug 充当唯一ID。

var json = [
   {
       id: 1,
       name: 'BInit',
       salary: 20000,
       department_slug: "it",
       department: 'IT'
   },
   {
       id: 2,
       name: 'BaaaInit',
       salary: 25000,
       department_slug: "hr",
       department: 'HR'
   },
   {
       id: 3,
       name: 'At',
       salary: 15000,
       department_slug: "finance",
       department: 'FInance'
   },
   {
       id: 4,
       name: 'aas',
       salary: 35000,
       department_slug: "finance",
       department: 'FInance'
   }
];

var depTotalSalaries = {};

for(var i=0; i<json.length; i++) {
  if (!depTotalSalaries[json[i].department_slug]) {
    depTotalSalaries[json[i].department_slug] = json[i].salary;
  } else {
    depTotalSalaries[json[i].department_slug] += json[i].salary;
  }
}

var maxSalary = 0;
var departments = Object.keys(depTotalSalaries);
for(var i=0; i<departments.length; i++){
  maxSalary = Math.max(maxSalary, depTotalSalaries[departments[i]])
}

for(var i=0; i<departments.length; i++){
  if (depTotalSalaries[departments[i]] == maxSalary) {
    console.log(departments[i], maxSalary);
  }
}

Answer 2

我会做的是这样的：

<Steps direction="vertical" current={1}>
  <Step title="Finished" icon={1} description="This is a description." />
  <Step title="In Progress" icon={2} description="This is a description." />
  <Step title="Waiting" icon={3} description="This is a description." />
</Steps>

来源： https://flaviocopes.com/how-to-sort-array-of-objects-by-property-javascript/

Answer 3

在下面的示例中使用array.reduce

var json = [
   {
       id: 1,
       name: 'BInit',
       salary: 20000,
       department_slug: "it",
       department: 'IT'
   },
   {
       id: 2,
       name: 'BaaaInit',
       salary: 25000,
       department_slug: "hr",
       department: 'HR'
   },
   {
       id: 3,
       name: 'At',
       salary: 15000,
       department_slug: "finance",
       department: 'FInance'
   },
   {
       id: 4,
       name: 'aas',
       salary: 35000,
       department_slug: "finance",
       department: 'FInance'
   }
];
const max = json.reduce(function(old, item) {
    return (old.y > item.y) ? old : item
}) 
console.log('max', max.salary);

Answer 4

更老套的方法：按薪水排序，然后从排序列表中选择第一个元素：

var json = [
   {
       id: 1,
       name: 'BInit',
       salary: 20000,
       department_slug: "it",
       department: 'IT'
   },
   {
       id: 2,
       name: 'BaaaInit',
       salary: 25000,
       department_slug: "hr",
       department: 'HR'
   },
   {
       id: 3,
       name: 'At',
       salary: 15000,
       department_slug: "finance",
       department: 'FInance'
   },
   {
       id: 4,
       name: 'aas',
       salary: 35000,
       department_slug: "finance",
       department: 'FInance'
   }
];

var sorted = json.sort((a, b) => a.salary > b.salary ? -1 : 1)
// sorted[0] is the highest salary

请注意，Array.sort会更改源，因此，如果您关心列表的原始排序，请不要使用此方法。

在数组中找到薪水最高的部门

4 个答案: